This is more to do with mathematics than physics,
but the square root of gravity on its own means nothing, its simply a acceleration due to gravity near the earth surface.
trying to find the speed of a falling object is a simple conservation of energy problem, then it has a meaning in that context.
however standing alone, it has no bearing to the real world. it is simply a mathematical term or construct we use in order to explain the real world. you see this all over the place in physics, you just have to get used to it.
for example:
mv^2=mhg
v^2=gh
v= SQRT(gh)
=SQRT(g)SQRT(h)
so SQRT means nothing on its own, simply a mathematical term to used to calculate the effects and actions in the real world.
i cant really compare it to Pi, sorry
but i hope you have a better understanding :)
Answer:
The self-inductance is ![L = 0.0053 \ H](https://tex.z-dn.net/?f=L%20%3D%20%200.0053%20%5C%20H)
Explanation:
From the question we are told that
The number of loops is ![N = 900](https://tex.z-dn.net/?f=N%20%20%3D%20%20900)
The length of the rod is ![l =6 \ cm = 0.06 \ m](https://tex.z-dn.net/?f=l%20%20%3D6%20%5C%20cm%20%20%3D%200.06%20%5C%20m)
The radius of the rod is ![r = 1 \ cm = 0.01 \ m](https://tex.z-dn.net/?f=r%20%3D%20%201%20%5C%20cm%20%3D%20%200.01%20%5C%20m)
The self-inductance for the solenoid is mathematically represented as
![L = \frac{\mu_o * A * N^2 }{l}](https://tex.z-dn.net/?f=L%20%3D%20%20%5Cfrac%7B%5Cmu_o%20%20%2A%20A%20%20%2A%20%20N%5E2%20%7D%7Bl%7D)
Now the cross-sectional of the solenoid is mathematically evaluated as
![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20r%5E2)
substituting values
![A =3.142 * 0.01 ^2](https://tex.z-dn.net/?f=A%20%3D3.142%20%2A%20%20%200.01%20%5E2)
![A = 3.142 *10^{-4} \ m^2](https://tex.z-dn.net/?f=A%20%3D%203.142%20%2A10%5E%7B-4%7D%20%5C%20%20m%5E2)
and
is the permeability of free space with a value ![\mu_o = 4\pi * 10^{-7} N/A^2](https://tex.z-dn.net/?f=%5Cmu_o%20%20%3D%20%20%204%5Cpi%20%2A%2010%5E%7B-7%7D%20N%2FA%5E2)
substituting values into above equation
![L = \frac{ 4\pi * 10^{-7} ^2* 3.142*10^{-4} * 900^2 }{0.06}](https://tex.z-dn.net/?f=L%20%3D%20%20%5Cfrac%7B%20%20%204%5Cpi%20%2A%2010%5E%7B-7%7D%20%5E2%2A%20%203.142%2A10%5E%7B-4%7D%20%20%2A%20%20900%5E2%20%7D%7B0.06%7D)
![L = 0.0053 \ H](https://tex.z-dn.net/?f=L%20%3D%20%200.0053%20%5C%20H)
Answer:
The correct answer to the following question will be "
".
Explanation:
According to the question,
⇒ ![TCos \theta-F_{s}=0](https://tex.z-dn.net/?f=TCos%20%5Ctheta-F_%7Bs%7D%3D0)
⇒
...(equation 1)
![\sum F_{y}](https://tex.z-dn.net/?f=%5Csum%20F_%7By%7D)
⇒ ![TSin \theta+F_{N}=m_{g}](https://tex.z-dn.net/?f=TSin%20%5Ctheta%2BF_%7BN%7D%3Dm_%7Bg%7D)
⇒
...(equation 2)
Now,
From equation 1 and equation 2, we get
⇒ ![T_{m} Cos \theta = \mu_{s}F_{N}](https://tex.z-dn.net/?f=T_%7Bm%7D%20Cos%20%5Ctheta%20%3D%20%5Cmu_%7Bs%7DF_%7BN%7D)
On putting the value of
, we get
⇒ ![T_{m} Cos\theta = \mu_{s}(M_{g}-T_{m}Sin \theta)](https://tex.z-dn.net/?f=T_%7Bm%7D%20Cos%5Ctheta%20%3D%20%5Cmu_%7Bs%7D%28M_%7Bg%7D-T_%7Bm%7DSin%20%5Ctheta%29)
⇒ ![\mu_{s}=\frac{T_{m}Cos\theta}{M_{g}-T_{m}Sin\theta}](https://tex.z-dn.net/?f=%5Cmu_%7Bs%7D%3D%5Cfrac%7BT_%7Bm%7DCos%5Ctheta%7D%7BM_%7Bg%7D-T_%7Bm%7DSin%5Ctheta%7D)
Its b<<<<<<<<<<<<<<<<<<<<,\
In the formation of mountain ranges and all other landforms, there is always a cycle involved. As one mountain comes up, another land gets pushed down into the hot mantle, where the rock will melt. Due to convection currents, the tectonic plates move and their boundaries cause them to interact with each other. As mountain ranges are formed, other land gets pushed up forming what we know are mountains, with rising magma from other parts of the world solidifying creating new rock to fill the empty space.