Here we go again lol
Answer: Experimental probability of landing on white = 177/1000.
Theoretical probability of landing on white = 1/5.
The larger the amount of spins, the greater the likelihood that the experimental probability will be close to the theoretical.
Answer:
Subtract 3 from both sides.
Step-by-step explanation:
x + 3 = 5
x = 5 - 3
<u>x = 2</u>
I know I`m late sorry, still wanted to answer
. _ .
Answer:
=0.5278
Step-by-step explanation:
a) The first die roll is bigger than the second or the first roll is a 3
Cases for 2 rolls are
(1,1)(1,2)(1,3)....(1,6),(2,1)(2,2)..... (total 36)
We will get 6 cases when they are equal and 15 when 1st is bigger and 15 when 1st is smaller
So
Let A is the event when first roll bigger
B is the event when First roll=3
So
P(A)=15/36
P(B) =1/6
P(A and B)=2/36
So
P(A or B)=P(A)+P(B)-P(A and B)
=15/36+1/6-2/36
=19/36
=0.5278
Answer:
C. The degree of dependence among the observation is negligible.
Step-by-step explanation:
The conditions for performing a t-procedure when constructing a t-interval are;
1) The samples observation should be independent of each other
2) The use of a random sample or experiment for the procedure
3) Ensure the normality of the data of the dependent variable
Given that surveys usually involve sampling without replacement from a population which is finite can not be taken as independent Bernoulli trials however, it is allowable to still consider samples independent when they are less than 10% the size of population
Therefore, the reason for the condition is to ensure that the population to sample size ratio is large enough and that the degree of dependence among the observation is negligible.
Answer:
x₁ = - 4 + √31
x₂ = - 4 - √31
Step-by-step explanation:
x² + 8x = 15
x² + 8x - 15 = 0
x = [- 8 ± √8² - 4×1×(-15)]/(2×1)
x = (-8 ± 2√31)/2
x₁ = (-8 ± 2√31)/2
x₁ = - 4 + √31
x₂ = - 4 - √31
