Answer:
-1.19 m
Explanation:
R1 = + 4 cm
R2 = - 15 cm
n = 1.5
distance of object, u = - 1 m
let the focal length of the lens is f and the distance of image is v.
use lens makers formula to find the focal length of the lens
By substituting the values, we get
.... (1)
By using the lens equation
from equation (1)
v = -1.19 m
Explanation:
(i)
O is the object and I is the image.
The image formed is enlarged and it is erect. So the magnification will be positive (+) and greater than 1.
Refer above image. 1
(ii)
O is the object and I is the image.
The image formed is diminished and erect. So the magnification will be positive (+) and less than1.
Refer above image. 2
(iii)
The image will be formed as the 2F on the other side of the lens and it will be of same of the object.
∑ Hey, Lethality ⊃
Answer:
5 x 5 = 30
6.0 x 70 = 400
Explanation:
<u><em>Given:</em></u>
<em>Multiply each of these numbers using SIG FIGS. (Significant Figures)</em>
<em>5 x 5</em>
<em />
<em>6.0 x 70</em>
<em />
<u><em>Solve:</em></u>
<em />
<em>-------------------------------------------------------------------------------------------------------------</em>
- <em>5 x 5</em>
- <u><em>2</em></u><em>5</em>
- <em>30</em>
<em>Answer : 30</em>
<em>Significant Figures: 1</em>
<em>-------------------------------------------------------------------------------------------------------------</em>
<em>6.0 x 70</em>
<u><em>4</em></u><em>20</em>
<em>400</em>
<em>Answer: 400</em>
<em>Significant Figures: 1</em>
<em>-------------------------------------------------------------------------------------------------------------</em>
<em />
<u><em>xcookiex12</em></u>
<em>8/23/2022</em>
Refer to the figure below.
R = resistance.
Case 1:
The voltage source is V₁ and the current is 10 mA. Therefore
V₁ = (10 mA)R
Case 2:
The voltage source is V₂ and the current is 8 mA. Therefore
V₂ = (8 mA)R
Case 3:
The voltage across the resistance is V₁ - V₂. Therefore the current I is given by
V₁ - V₂ = IR
10R - 8R = (I mA)R
2 = I
The current is 2 mA.
Answer: 2 mA