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antoniya [11.8K]
3 years ago
6

A rock is dropped from the surface into a pit. It hits the bottom of the pit in 5.0 seconds. A second rock is then dropped into

a second pit, where it hits the bottom in 10 seconds. How much deeper is the second pit compared to the first pit? Neglect air resistance
Physics
2 answers:
Kobotan [32]3 years ago
6 0
The first pit is 125 meters deep while the second pit is 500 meters deep
Sergio [31]3 years ago
5 0

Answer

second pit is 4 times deeper compared to the first pit.

Explanation

The first pit is 125 meters deep while the second pit is 500 meters deep

We know from second equation of motion

s=ut+.5at^2..........(1)

here s-depth of pit

u=0 (initial velocity0

a-gravitational acceleration (a=g=9.8ms^{-2}

t-time

when t=5second

put value of t,a and u in equation 1

s_{1}=0+.5\times 9.8ms^{-2}\times 5^2s^2

s_{2}=122.5m

similarly when t=10s

put value of t,a and u in equation 1

s_{2}=0+.5\times 9.8ms^{-2}\times10^2s^2

s_{2}=490m

therefore,

\frac{s_{2}}{s_{2}}=\frac{490}{122.5}\\\frac{s_{2}}{s_{2}}=4

It means second pit is 4 times deeper compared to the first pit.

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3 0
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Two objects attract each other gravitationally. If the distance between their centers decreases by a factor of 2, how does the g
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The gravitational force between them increases by a factor of 4

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Hence,the gravitational force becomes:

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Read 2 more answers
A stone is thrown horizontally at 60.0 m/sm/s from the top of a very tall cliff. Calculate its horizontal position and vertical
svp [43]

Answer:

X-Positions:                                         Y-Positions

x(0) = 0                                                   y(0) = 0

x(2) = 120 m                                           y(2) = 19.6 m

x(4) = 240 m                                          y(4) = 78.4 m

x(6) = 360 m                                          y(6) = 176.4 m

x(8) = 480 m                                          y(8) = 313 m

x(10) = 600m                                         y (10) = 490 m

Explanation:

X-Positions

  • First, we choose to take the horizontal direction as our x-axis, and the positive x-axis as positive.
  • After being thrown, in the horizontal direction, no external influence acts on the stone, so it will continue in the same direction at the same initial speed of 60. 0 m/s
  • So, in order to know the horizontal position at any time t, we can apply the definition of average velocity, rearranging terms, as follows:

       x = v_{ox} * t = 60.0 m/s * t(s)

  • It can be seen that after 2 s, the displacement will be 120 m, and each 2 seconds, as the speed is constant, the displacement will increase in the same 120 m each time.

Y-Positions

  • We choose to take the vertical direction as our y-axis, taking the downward direction as our positive axis.
  • As both axes are  perpendicular each other, both movements are independent each other also, so, in the vertical direction, the stone starts from rest.
  • At any moment, it is subject to the acceleration of gravity, g.
  • As the acceleration is constant, we can find the vertical displacement (taking the  height of the cliff as the initial reference level), using the following kinematic equation:

       y = \frac{1}{2} * g* t^{2} = \frac{1}{2} * 9.8 m/s2 * t(s)^{2}

  • Replacing by the values of t, we get the following vertical positions, from the height of the cliff as y = 0:
  • y(2) = 2* 9.8 m/s2 = 19.6 m
  • y(4) = 8* 9.8 m/s2 = 78.4 m
  • y(6) = 18*9.8 m/s2 = 176.4 m
  • y(8) = 32*9.8 m/s2 = 313.6 m
  • y(10)= 50 * 9.8 m/s2 = 490.0 m
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3 years ago
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