Taro's error is when he stated that the total energy of the ball and the club system is increasing. This is not true. The total energy of the system is not increasing. According to the first law of thermodynamics, <span>total energy of a system is always constant; energy can be transformed from one form to another however it cannot be created or destroyed. </span><span>Energy is conserved. </span>So, for this problem the total energy of the system should remain constant at all times.
Answer:
50J
Explanation:
At the top you have(A)
KE_a = O
PE_a = 100J
KE + PE = 100J
At the bottom you have (C)
KE_c= 100J
PE_c=0J
KE+PE = 100J
At point C:
You are at half the height.
We know that at H, PE =100J
PE_c = mgH
At C,
PE_c= mg (H/2) *at half the height
*m and g stay the same
Intuitively, the higher you are, the more potential energy you have.
If you decrease the height by a half, your PE will also decrease
At A:
PE_a / (mg) = H
At B:
PE_b / (mg) = H/2
to also get H on the right hand side, multiply by 2
2 (PE_b/ (mg))= H
2PE_b / (mg) = H
Ok, now that we have set up 2 equations (where H is isolated), find PE at B
AT A = AT B *This way you are saying that H = H (you compare both equations)
PE_a / (mg) = 2x PE_b / (mg)
*mg are the same for both cancel them (you can do that because of the = sign)
PE_a = 2PE_b
We know that PE_a = 100J
100J/2 = PE_b
PE at b = 50J
**FIND KE at b
We know that
KE_b + PE_b is always 100J
100J = 50J + KE_b
KE_b = 50J
Explanation:
ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES
LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s
= 33.52 m/s <em>v</em> = 53.67 m/s <em>x</em> = 3220 m
PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN
DE GALILEO GALILEI
<em>a</em> = =
AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON
F = 75 kg() = 40.9 N