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Alchen [17]
3 years ago
11

The mass of the bicycle and rider is 60 kg and the total area of the tyres in contact with

Physics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

a little

Explanation:

First of all, it's not how you spell "tyres", it is tires.

Second of all, you already know the Mass so what you need to find out now is  contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!

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A ball is projected horizontally from the top of a hill with a velocity of 30m/s if it reaches the ground 5sec later the height
Vikki [24]

Answer:

The hill is a total of 150 meters tall

Explanation:

30×5=150

7 0
3 years ago
A rock is stuck deep in the dirt. When you pull on the rock to remove it, what type of force are you exerting?
aleksandrvk [35]
It is Tension as the other 3 answer choices would not make sense. Compression would mean you are pressing the rock on both sides or in this case, pushing it into the dirt. It can't be nuclear force as you are pulling out a rock. Air resistance would not make sense either as there is no air involved in the scenario at all.
4 0
3 years ago
Read 2 more answers
It takes 160 kj of work to accelerate a car from 24.0 m/s to 27.5 m/s. what is the car's mass?
ankoles [38]
Work-Energy :W = 1/2 m ( Vf^2 -Vo^2 )
Vo = 24.0 m/s Initial speed 
 Vf = 27.5 m/s  Final speed 

W = 1/2 m ( Vf^2 -Vo^2 )
160 kj = 1/ 2 m ( 27.5^2  -24.0 ^2)
160kj =  4680 x m
convert kilo joules to jeoules                     160000 j = 4689 xm
m = 160000 j/4689
m = 34.18 kg
4 0
4 years ago
A 42.2 kg sled is pulled forward
zaharov [31]

The net force on the sledge  is 31.64N.

Frictional force = µkR

                         = 0.269 x 42.2 x 9.81 = 111.36

net force = 143N - 111.36N

               = 31.64N

refer  brainly.com/question/24557767

#SPJ2

     

7 0
2 years ago
An object starts at 4m/s and accelerates to 6m/s in 10 seconds. Find its displacement.
Natalka [10]

Answer:

Explanation:

The 2 equations we need here are, first:

a=\frac{v_f-v_0}{t} and then once we solve for the acceleration here:

v^2=v_0^2+2aΔx

Solving for acceleration:

a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2} and now we will use that in the other equation:

6^2=4^2+2(\frac{1}{5})Δx and

36 = 16 + \frac{2}{5}Δx and

20 = \frac{2}{5}Δx and

\frac{5}{2}(20)= Δx so

Δx = 50 m

6 0
3 years ago
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