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Answer:
- 0.100
Step-by-step explanation:
Length of the ladder, H = 6 m
Distance at the bottom from the wall, B = 1.3 m
Let the distance of top of the ladder from the bottom at the wall is P
Thus,
from Pythagoras theorem,
B² + P² = H² .
or
B² + P² = 6² ..............(1) [Since length of the ladder remains constant]
at B = 1.3 m
1.3² + P² = 6²
or
P² = 36 - 1.69
or
P² = 34.31
or
P = 5.857
Now,
differentiating (1)
at t = 2 seconds
change in B = 0.3 × 2= 0.6 ft
Thus,
at 2 seconds
B = 1.3 + 0.6 = 1.9 m
therefore,
1.9² + P² = 6²
or
P = 5.69 m
on substituting the given values,
2(1.9)(0.3) + 2(5.69) × 
= 0
or
1.14 + 11.38 × = 0
or
11.38 × = - 1.14
or
= - 0.100
here, negative sign means that the velocity is in downward direction as upward is positive
Answer:
A) CUB
Step-by-step explanation:
Of the suggested planes, only CUB contains both points C and T.
___
<em>Comments on the other answer choices</em>
BED contains point T, but not C
ACE contains point C, but not T
ABE contains neither C nor T
Answer:
The surface area of the figure = 962 ft²
Step-by-step explanation:
The rectangle dimensions and its area given below
Dimensions Number Area
12 x 7 2 12 x 7 x 2 = 168
16 x 7 1 16 x 7 = 112
12 x (16 + 5) 1 12 x 21 = 252
16 x 12 1 16 x 12 = 192
16 x 13 1 16 x 13 = 208
Triangle dimensions
Dimensions Number Area
b = 12 & h = 5 2 bh/2 = (12*5)/2 = 30
To find total area
Total area = 168 + 112 + 252 + 192 + 208 + 30 = 962 ft²
Answer:
Domain: (-∞, ∞)
Range: (-∞, ∞)
Step-by-step explanation:
The domain are the x-values included in the function (the horizontal axis).
The range are the y-values included in the function (the vertical axis).
The two arrows on the ends of the line (pointing upwards and downwards respectively) indicate that the function goes in those direction for infinity. Therefore, if there are an infinite amount of y-values, the range is (-∞, ∞).
While the slope is quite steep, there is still a slope and slowly "expands" the line on the horizontal axis. Because there is no limit to the y-values, the domain will also expand infinitely. Therefore, the domain is also (-∞, ∞).
