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2 years ago

Find the center of the galaxy with Shapley method

Physics

1 answer:

Natalija [7]2 years ago

5 0

Answer:

Calculating Center

Shapley correctly determined the galactic center of the Milky Way to be located in the constellation of Sagittarius. He did this by mapping out a three-dimensional distribution of the globular clusters.

Explanation:

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An object was thrown at a certain angle above the ground.It reaches a maximum height of 42.50 meters and hits back the ground 76

aksik [14]

Answer:

Explanation: Please see my attached calculations.

7 0

3 years ago

In which phase of matter are the atoms closely packed but still able to slide past each other?

borishaifa [10]

The phase of matter is the Solid Phase.

3 0

4 years ago

A car traveling on a straight road at 15.0 meters per second accelerates uniformly to a speed of 21.0 meters per second in 12.0

oksano4ka [1.4K]

<h2>Option 3, 216 m is the correct answer.</h2>

Explanation:

We have initial velocity, u = 15 m/s

Time, t = 12 seconds

Final velocity, v = 21 m/s

We have equation of motion v = u + at

Substituting

21 = 15 + a x 12

a = 0.5 m/s²

Now we have equation of motion v² = u² + 2as

21² = 15² + 2 x 0.5 x s

s = 216 m

Displacement = 216 m

Option 3, 216 m is the correct answer.

8 0

4 years ago

An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the ob

lorasvet [3.4K]

Answer:

the force of attraction between the two charges is 3.55 N.

Explanation:

Given;

first charge carried by the object, q₁ = 15.5 µC

second charge carried by the q₂ = -7.25 µC

distance between the two charges, r = 0.525 m

The force of attraction between the two charges is calculated as;

$F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N$

Therefore, the force of attraction between the two charges is 3.55 N.

3 0

3 years ago

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/

Artemon [7]

Complete Question

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope

Answer:

The value is $F = 150 \ N$