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Katena32 [7]
3 years ago
12

This is an electrical device that changes the voltage of electricity through the use of two set of coils

Physics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

The correct answer is a (TRANSFORMER). Trust me

Explanation:

Fynjy0 [20]3 years ago
3 0
Voltmeter is the right answer
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Pls help it’s easy ik but I want to make sure of them both I don’t have much time
LuckyWell [14K]

Answer:

To the right

Weight

Explanation:

8 0
2 years ago
Who was the first woman to compete and win a championship in the Olympics
natita [175]
Hélène de Pourtalès she was the first women
6 0
3 years ago
What is the resultant of the vectors shown?
ad-work [718]

Answer:

Option B

Explanation:

Option A is the wrong answer because the horizontal vector is in the opposite direction.

Option C is the wrong answer as the horizontal vector is in the opposite direction and all the vectors are connected head to tail [of the arrows] [Triangle law of vector addition]

Option D is the wrong answer as the horizontal vector is in the opposite direction.

5 0
2 years ago
Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force
Brilliant_brown [7]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where 
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
q_1=q_2=q=-1.6 \cdot 10^{-19}C

By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
5 0
3 years ago
MAJOR POINTS! Solve the system of equations to find <img src="https://tex.z-dn.net/?f=%20a_%7B2%7D%20%20" id="TexFormula1" title
Monica [59]
You are dealing with pulleys?

can be done with addition of the two equations to eliminate T.

(2^{*}) \quad {} -m_1 g \cos \theta + T = m_1 a _2
+
(4^{*}) \quad 3m_1 g - T = 3m_1 a_2
=

(-m_1 g \cos\theta  +  3m_1 g) + (T - T) = m_1 a _2 + 3m_1 a_2 \implies \\ \\&#10;(-m_1 g \cos\theta  +  3m_1 g) = 4m_1 a_2 \implies \\ \\&#10;m_1(- g \cos\theta  +  3g)= 4m_1 a_2

we can cancel m₁ by dividing both sides by it, assuming mass is not zero


(- g \cos\theta + 3g)= 4a_2 \implies \\ \\&#10;a_2 = \dfrac{- g \cos\theta + 3g}{4} \\ \\&#10;a_2 = \dfrac{- 9.80  \cos 60 + 3(9.80)}{4} \\ \\&#10;a_2 = 6.125 \text{m/s}^2&#10;

a₂ = 6.125 m/s² ( do significant digits if you need to)
6 0
3 years ago
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