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Katena32 [7]
3 years ago
12

This is an electrical device that changes the voltage of electricity through the use of two set of coils

Physics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

The correct answer is a (TRANSFORMER). Trust me

Explanation:

Fynjy0 [20]3 years ago
3 0
Voltmeter is the right answer
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sergij07 [2.7K]
{Answer}
A- (10kg sphere and 30m)

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2 years ago
A radio signal takes 1.28 s to travel from a transmitter on the Moon to the surface of Earth. The radio waves travel at 3.00108
yulyashka [42]

Answer:

s = 3.84 x 10⁸ m

Explanation:

The distance traveled by an object, while in uniform motion, is given by the following equation:

s = vt

where,

s = distance covered

v = speed

t = time interval

In this case:

s = distance between Moon and Earth = ?

v = speed of radio waves = 3 x 10⁸ m/s

t = time taken to travel = 1.28 s

Therefore,

s = (3 x 10⁸ m/s)(1.28 s)

<u>s = 3.84 x 10⁸ m</u>

3 0
3 years ago
The capacitance of a Pt-n-type GaAs Schottky diode is given by 1 (C(μF))2 = 1.0 × 105 − 2.0 × 105 V The diode area is 0.1 cm2. C
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built in potential Vbi = +0.5V

barrier height = 0.139 V

doping concentration = 5.39 × 10²³cm³

Explanation:

5 0
3 years ago
Look at the vector r plotted below
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2 years ago
A 23.0 kg bucket of water is suspended by a very light rope wrapped around a solid uniform cylinder 0.300 m in diameter with mas
nevsk [136]

Answer:

The tension in the rope is 49.66 N.

Explanation:

Given that,

Mass of bucket m= 23.0 kg

Diameter = 0.300 m

Mass of rope M= 13.0 kg

Height = 10.5 m

Suppose we need to find the tension in the rope while the bucket is falling.

We need to calculate the acceleration

Using balance equation

mg-T=ma..(I)

We need to calculate the tension in the rope

Using formula of tension

Tr=I\alpha

Tr=\dfrac{Mr^2}{2}\times\dfrac{a}{r}

T=\dfrac{Ma}{2}....(II)

Put the value of T in the equation (I)

mg-\dfrac{Ma}{2}=ma

a=\dfrac{mg}{m+\dfrac{M}{2}}

Put the value into the formula

a=\dfrac{23.0\times9.8}{23.0+\dfrac{13.0}{2}}

a=7.64\ m/s^2

Now, put the value of a in equation (II)

T=\dfrac{13.0\times7.64}{2}

T=49.66\ N

Hence, The tension in the rope is 49.66 N.

5 0
2 years ago
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