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3 years ago

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The volume of a rectangular prism is 420 cubic centimeters. The length, L, is 6 centimeters and the width, W, is 14 centimeters.

What is the height, H, in centimeters, of the rectangular prism?

1 answer:

Harman [31]3 years ago

4 0

Answer:

5 centimeters

Step-by-step explanation:

We know the equation to find volume is V = B x h, where B is the base of the prism. (It is also known as the simple V = l x w x h.)

No matter what equation you use, you will end up with V = l x w x h, since the base of a rectangular prism is length x width. So, we're going to plug in our known information to get 420 = 6 x 14 x h.

Then, we're going to multiply 6 x 14 to get 84. Now we have 420 = 84 x h. To isolate the h (in order to find what it is), we must divide both sides by 84.

420/84 = 5, so whats left of the equation is 5 = h, meaning your height is 5 centimeters.

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Answer:

205 : 41

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3 years ago

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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

<em>Find the distance AB</em>

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

<em>Find the distance BC</em>

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

<em>Find the distance CD</em>

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

<em>Find the distance DE</em>

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

<em>Find the distance AE</em>

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

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3 years ago

Solve the system of linear equations by substitution.<br><br> y = 2x + 8<br> y = -2x

posledela

Answer:

(- 2, 4 )

Step-by-step explanation:

y = 2x + 8 → (1)

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substitute y = 2x + 8 into (2)

2x + 8 = - 2x ( add 2x to both sides )

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4x = - 8 ( divide both sides by 4 )

x = - 2

substitute x = - 2 into (2)

y = - 2(- 2) = 4

solution is (- 2, 4 )

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2 years ago

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kaheart [24]

Answer:
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Step-by-step explanation:
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The answer is A!!! Hope that helped :)

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2 years ago