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lesantik [10]
3 years ago
5

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

information?
A: They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties.
B: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.
C: They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties.
D: They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.
Physics
2 answers:
Thepotemich [5.8K]3 years ago
6 0

The answer is:

B)They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

The explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior. All the members of a family of elements have the same number of valence electrons and similar chemical properties.

A period is a horizontal row of elements on the periodic table. For example, the elements sodium ( Na ) and magnesium ( Mg ) are both in period 3. The elements astatine ( At ) and radon ( Rn ) are both in period 6.

AnnZ [28]3 years ago
5 0

Answer:

(B)

Explanation:

jus took the test on edg

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monitta

Answer:110

Explanation:

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3 years ago
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
4 years ago
. If she
I am Lyosha [343]

Answer:

9 meters

Explanation:

Given:

Mass of Avi is, m=40\ kg

Spring constant is, k=176,400\ N/m

Compression in the spring is, x=20\ cm=0.20\ m

Let the maximum height reached be 'h' m.

Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.

So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.

Decrease in elastic potential energy is given as:

EPE=\frac{1}{2}kx^2\\EPE=\frac{1}{2}\times 176400\times (0.20)^2\\EPE=88200\times 0.04=3528\ J

Now, increase in gravitational potential energy is given as:

GPE=mgh=40\times 9.8\times h=392h

Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,

392h=3528\\\\h=\frac{3528}{392}\\\\h=9\ m

Therefore, Avi will reach a maximum height of 9 meters.

6 0
3 years ago
A spider twirls a 25 mg fruit fly around in a circle with radius 17.6 cm at the end of a web. If the velocity of the fly is 110
olchik [2.2K]

Answer:

Fc =  1.7x10^-4 N

Explanation:

Convert everything to proper units:

m = 25mg = 2.5x10^-5 kg

r = 17.6cm = 0.176m

v = 110cm/s = 1.1m/s

the formula for centripetal force is Fc = mv^2 / r

Plug everything and solve for Fc;

fc = (2.5x10^-5)(1.1^2) / 0.176

Fc =  1.7x10^-4 N

8 0
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If the car has a mass of 1200 kg, how much force must the engine provide?
vazorg [7]

Force in Newtons =

(1200)•(the rate of acceleration you want)

It depends on how fast you want to accelerate.

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