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3 years ago

How many primary tectonic plates make up the surface of Earth?

2 answers:

7 0

There are about 7 or 8 primary tectonic plates. The lithosphere is made of about a dozen plates. The plates fit together like the pieces of a jigsaw puzzle. However, the plates can move. This causes earthquakes, volcanoes, and mountains to form.

Hope it helps

deff fn [24]3 years ago

4 0

There are 15 to 20 primary tectonics that make up the surface of Earth. They are called Lithosphere.

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Baking soda reacts with vinegar and forms a gas why is it chemical

777dan777 [17]

Its a chemical reaction because both are affected by the reaction and changed. hope this helps (ू• o •ू )

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3 years ago

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What properties are attributed to a solid with the type of bonding represented in the picture?

Elanso [62]

B it is a cold melting point

6 0

3 years ago

What type of reaction is this?—- Large Compound=Element A+Element B

Sav [38]

This reaction is decomposition. It is the breakdown of a compound into simpler and smaller elements.

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2 years ago

Which statement is correct? A. pKa is not an indicator of acid strength. B. An acid with a small Ka is stronger than an acid wit

Svetradugi [14.3K]

Answer:

Explanation:

Since [pKa = - log Ka]....hence..,the larger the Ka value,the stronger the acid is..so this means that the pKa is vice versa

Saying that the smaller the pKa value..the stronger the acid is.

3 0

3 years ago

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A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago