of oxygen at STP would be required to react completely with 38.8g of propane.
<u>Given that :</u>
molar mass of propane = 44 g/mol
mass of propane = 38.8 g
∴ Moles present in 38.8 g of propane = = 0.88 mole
<u>applying rule of balanced equations </u>
1 mole of propane = 5 moles of oxygen
0.88 mole of propane = 5 * 0.88 = 4.4 moles of oxygen
Note : volume of 1 mole of oxygen at STP =
∴Total volume of oxygen required at STP = 22.4 * 4.4 =
Hence we can conclude that the volume of oxygen at STP required to react completely
Learn more : brainly.com/question/16998374
Answer:
The answer to your question is: C. A gas turning into plasma.
Explanation:
The plasma state is similar to the gas state, but these to states behave very different.
Like gases, plasma does not have a shape or fixed volume and are less denser than solids and liquids.
But, unlike gases, plasma are made up of atoms in which some of the electrons have been stripped away.
Answer:
Heyy Mason, I donʻt know if you got the answer already but I was also trying to find the answer haha and came across this. Might as well help you since I eventually stopped being lazy and did the calculations...The answer is 144 L.
Explanation:
Use Charles Law to solve this
V1 = 50.0L
T1 = 205K
V2 = ?
T2 = 590K
using V1/T1 = V2/T2 plug in the numbers
50.0L/205K = V2/590K
Switch it around so V2 is isolated
V2 = 590K(50.0L/205K)
cancel out the K
solve
you get 143.90243
round to 144