The answer is- 
is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.
Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.
Determine the molecular geometry of .
- Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
- According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
- Now, calculate the total number of valence electrons in .
Valence electrons of S = 6
Valence electrons of F = 7
Thus, the valence electrons in are-
- The Lewis structure of is - (Image attached).
- In the structure, the number of atoms bonded to central atom (S) = 6.
- Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
- Electronic geometry in case of 6 bond pairs is octahedral.
- Molecular geometry us also octahedral with bond angles 90°.
- Central atom is sp3d2 hybridised.
- is a non-polar molecule.
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Answer: Theoretical yield of 
produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of 
produce = 3 moles of
Thus 0.28 moles of will produce=
of
Mass of 
Thus theoretical yield of produced by 8.96 g of S is 33.6 g
Once you identify the compound as Ionic<span>, </span>Molecular, or an Acid, follow the individual ... chemicalformulas<span>, write </span>whether<span> the compound is </span>ionic or molecular<span>, and ...</span>
The answer is Metalloids!
Answer:
The answer to your question is: letter c (96%)
Explanation:
Indium -113 (112-9040580 amu) ₁₁₃In
Indium-115 (114.9038780 amu) ₁₁₅In
Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In
Formula
Atomic mass = m₁(%₁) +m₂(%₂) / 100
%₁ = x I established this is an equation
%₂ = 100 - x
Substituting values
114.82 = 112.8040x + 114.9039(100-x) /100 and know we expand and simplify
114.82 = 112.8040x + 11490.39 - 114.9039x /100
11482 = 112.8040x -114.9039x +11490.39
11482 - 11490.39 = 112.8040x -114.9039x
-8.39 = -2.099x
x = 3.99
Then % of Indium-115 = 100 - 3.99 = 96
