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3 years ago

List 3 scenarios for a substance being classified as a weak acid

2 answers:

4 0

A way to classify an acid as being weak is to determine how strongly the substance conducts electricity. If the acid or base conducts electricity strongly, it is a strong acid or base. If the acid or base conducts electricity weakly, it is a weak acid or base.

Vesna [10]3 years ago

4 0

Answer:

3 scenarios:

1. acetic acid, organic acid that comes from vinager

2. citric acid, that is present in some fruits

3. phosphoric acid , present in sodas

Explanation:

A weak acid is the one that partially transferres its proton (H+) to a water molecule ( partial dissociation), and usually a part of the original acid (HA) remains after the process of dissociation; that is why, a dissociation reaction of a weak acid is represented with an arrow of both ways.

$HA ⇌ H^{+} +A^{-}$

As we can see, the acetic acid, citric acid and phosphoric acid are great examples of weak acid. Their pH is higher thanks to its low dissociation, and they can even be eaten in low concentrations.

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The N2O4−NO2 reversible reaction is found to have the following equilibrium partial pressures at 100∘C. Calculate Kp for the rea

timofeeve [1]

Answer:

$K_{p}$ for the reaction is 18.05

Explanation:

Equilibrium constant in terms of partial pressure ( $K_{p}$ ) for this reaction can be written as-

$K_{p}=\frac{P_{NO_{2}}^{2}}{P_{N_{2}O_{4}}}$

where $P_{NO_{2}}$ and $P_{N_{2}O_{4}}$ are equilibrium partial pressure of $NO_{2}$ and $N_{2}O_{4}$ respectively

Hence $K_{p}=\frac{(0.095)^{2}}{(0.0005)}$ = 18.05

So, $K_{p}$ for the reaction is 18.05

3 0

3 years ago

What is the volume of 300. g of mercury vapor at 822K and 0.900 atm?

Dominik [7]

Answer:

112.2L

Explanation:

Volume (V) = 300g

Temperature (T) = 822K

Pressure (P) = 0.9atm

using the ideal gas equation;

$PV = nRT\\\\ V = \frac{nRT}{P}$

Molar gas constant (R) = $0.0821L.atm/mol.K$

Mole (n) = $\frac{Mass (m)}{Molar mass (M)}$ Molar mass of Mercury = 200.59g/mol

$n = \frac{300g}{200.59 g/mol} \\$

= 1.496mol

Now, the volume can be calculated;

V = $\frac{1.496mol* 0.0821L.atm/mol.K*822K}{0.9atm}$

∴Volume of mercury = $112.2L$

8 0

2 years ago

Complete the three words. The oxidation state tells you how many electrons an atom has g....................... , l.............

fgiga [73]

Answer:Gained, Lost , Shared

Explanation:

The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.

Oxidation state is defined as the the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.

----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state to become stable forming the NaCl compound.

To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3, The phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with Phosphorous having +3 and the chlorine atoms having -1 oxidation states

8 0

3 years ago

True or false? Covalent molecules are formed when non-metal atoms share electrons with other non-metal atoms.

Tomtit [17]

Answer:

true

covalent bonds are between non metals and nonmetals. and they are sharing electrons.

7 0

2 years ago

William measures a test tube and finds that the mass of the test tube is 5g. He places the lone reactant in the test tube and fi

iogann1982 [59]

86 percent is the percent yield for this experiment if he expected to produce 5g of product.

Explanation:

Given that:

mass of test tube = 5 grams

mass of test tube + reactant is 12.5 grams

mass of reactant = ( mass of test tube + reactant ) - (mass of test tube)

mass of reactant = 12.5 -5

= 7.5 grams

when 7.5 grams of reactant is heated mass of test tube was found to be 9.3 grams.

so mass of product formed = 9.3 - 5

= 4. 3 grams of product is formed (actual yield)

However, he expected the product to be 5 grams (theoretical yield)

Percent yield = $\frac{actual yield}{theoretical yield}$ x 100

putting the values in the formula:

percent yield = $\frac{4.3}{5}$ x 100

= 86 %

86 percent is the percent yield.

5 0

3 years ago