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amm1812
3 years ago
15

2. Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)

Chemistry
1 answer:
shtirl [24]3 years ago
4 0
Balanced equation: 2Al+Fe2O3–> Al2O3+2Fe

Using mole calculations you can find that 10g of Al produces 24.3g of Fe under the conditions described
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Which characteristics is not a characteristic of plastic?
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Determine molar mass of Mn (ClO3)3
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8 0
3 years ago
4) 10.00 mL of sulfuric acid is neutralized in a titration using 18.54 mL of 0.100 M NaOH.
sdas [7]

Answer:

a) H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

b) M_{H_2SO_4}=0.0927M

Explanation:

Hello!

In this case, for this acid-base reaction which also known as a neutralization because sulfuric acid is neutralized with sodium hydroxide, we can write the undergoing chemical reaction as shown below:

H_2SO_4+NaOH\rightarrow Na_2SO_4+H_2O

However, it needs to be balanced as two sodium atoms are yielded:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

Next, since there is a 1:2 mole ratio between the acid and the base, at the equivalence point, at which the moles of acid and base are consumed, we write:

2n_{H_2SO_4}=n_{NaOH}

Which can also be written in terms of the given volumes and concentration of the base:

2M_{H_2SO_4}V_{H_2SO_4}=M_{NaOH}V_{NaOH}

In such a way, we solve for the concentration of sulfuric acid as shown below:

M_{H_2SO_4}=\frac{M_{NaOH}V_{NaOH}}{2V_{H_2SO_4}} =\frac{18.54mL*0.100M}{2*10.00mL}\\\\ M_{H_2SO_4}=0.0927M

Best regards!

5 0
3 years ago
Consider the reaction: 2NO(g) O2(g) --> 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is
poizon [28]

Answer:

a. 0.0022 M/s

b. 0.0011 M/s

Explanation:

Let's consider the following reaction.

2 NO(g) + O₂(g) → 2 NO₂(g)

The rate of disappearance of NO is 0.0022 mol NO. L⁻¹.s⁻¹

<em>a. At what rate is NO₂ being formed?</em>

The molar ratio of NO to NO₂ is 2:2. The rate of formation of NO₂ is:

\frac{0.0022molNO}{L.s} .\frac{2molNO_{2}}{2molNO} =\frac{0.0022molNO_{2}}{L.s}

<em>b. At what rate is molecular oxygen reacting?</em>

The molar ratio of NO to O₂ is 2:1. The rate of disappearance of O₂ is:

\frac{0.0022molNO}{L.s} .\frac{1molO_{2}}{2molNO} =\frac{0.0011molO_{2}}{L.s}

8 0
3 years ago
Read 2 more answers
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