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DaniilM [7]
2 years ago
13

To answer that question

Mathematics
1 answer:
Mars2501 [29]2 years ago
5 0
First, we get ax^2+bx+c. Next, we know that the line of symmetry is -b/2a. Since we know that there is a maximum value, the parabola is facing downwards, so a is negative. For random numbers, we can say that a = -0.5 and b=-10 (b needs to be negative for -b/2a to equal -10), getting -0.5x^2-10x+c. Plugging -10 in for x (since -10 is the middle it is the max), we get -50+100=50. Since the maximum needs to be 5, not 50, we subtract 45 from the answer to get it and therefore make c = -45, getting -0.5x^2-10x-45
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17:3 and 15:60 Equivalent ratios
inessss [21]

Answer:

Step-by-step explanation:

17:3 is already in lowest terms. 17:3 = 34:6, 51:9, etc.

15:60 = 1:4

5 0
2 years ago
How do you solve this equation? -5/4+(-7/9)= Thanks
Klio2033 [76]

Answer:

-2 1/36 or -2.028

Step-by-step explanation:

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8 0
3 years ago
What is 23.5 in word form
3241004551 [841]
To hundred three hundred and five
6 0
3 years ago
Read 2 more answers
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
Akimi4 [234]
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is \mathbf 0. We have

\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function f(x,y,z) such that its gradient is equal to the given vector field, \mathbf f(x,y,z):

\nabla f(x,y,z)=\mathbf f(x,y,z)

For this to happen, we need to satisfy

\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}

From the first equation, integrating with respect to x yields

f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)

Note that g *must* be a function of y,z only.

Now differentiate with respect to y and we have

f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots

but this contradicts the assumption that g(y,z) is independent of x. So, the scalar potential function does not exist, and therefore the vector field is not conservative.
8 0
2 years ago
Help me!!!<br><br>A.18.6<br><br>B.15.2<br><br>C.25.2<br><br>D.17.1
andreyandreev [35.5K]

i believe its b

Step-by-step explanation:

7 0
2 years ago
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