Question

2FeCl3 + 3Mg → 3MgCl2 + 2Fe

Answer 1

Answer:

$\large \boxed{\text{A. 3.0 mol}}$

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               2FeCl₃ + 3Mg ⟶ 3MgCl₂ + 2Fe

n/mol:                     4.5

2 mol of FeCl₃ react with 3 mol of Mg

$\text{Moles of FeCl}_{3} = \text{4.5 mol Mg}\times \dfrac{\text{2 mol FeCl}_{3}}{\text{3 mol Mg}}= \textbf{3.0 mol Mg}\\\\\text{The reaction will need \large \boxed{\textbf{3.0 mol of Mg}} }$