4 Nitrogen monoxide reacts with oxygen like this:
1 answer:
a. mol O₂=0.5
b. volume O₂ = 25 cm³
c. i. the total volume of the two reactants = 75 cm³
c. ii. the volume of nitrogen dioxide formed = 50 cm³
<h3>Further explanation</h3>Reaction
2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)
a.
mol NO = 1
From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :
b.
From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles
Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :
c.
i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³
ii. the volume of nitrogen dioxide formed :
mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³
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Answer : The mass of required are, 35 kg
Explanation :
First we have to calculate the mass of .
The first step balanced chemical reaction is:
Molar mass of = 115 g/mole
Molar mass of = 87 g/mole
Let the mass of be, 'x' grams.
From the balanced reaction, we conclude that
As, of
react to give
of
So, of
react to give
of
And as we are given that the yield produced from the first step is, 65 % that means,
The mass of obtained = 0.4542x g
Now we have to calculate the mass of .
The second step balanced chemical reaction is:
Molar mass of = 87 g/mole
Molar mass of = 55 g/mole
From the balanced reaction, we conclude that
As, of
react to give
of
So, of
react to give
of
And as we are given that the yield produced from the second step is, 80 % that means,
The mass of obtained = 0.2296x g
The given mass of Mn = 8.0 kg = 8000 g (1 kg = 1000 g)
So, 0.2296x = 8000
x = 34843.20 g = 34.84 kg = 35 kg
Therefore, the mass of required are, 35 kg