Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Minus 3 from the 3 and the 18
It is true that a parallelogram has symmetry with respect to the point of intersection of its diagonals.
Both angles 2x+6 and 96 shown are vertically opposite angles and vertically opposite angles are always equal
so 2x+6 should be equal to 96
so 2x + 6 = 96
Now we have to solve for x here and have to get x by itself on left hand side
So first get rid of +6 by doing its opposite -6 on both sides
2x + 6 -6 = 96 -6
2x = 90
Now to get x by itself we have to get rid of 2, for that divide both sides by 2

x = 45
Hence proved that x = 45