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Marianna [84]
3 years ago
9

(2x^2+4x-3)-(2x^2+4x-3) show work mark brainliest

Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0

Solution: \left(2x^2+4x-3\right)-\left(2x^2+4x-3\right)=0

Steps:

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a, =2x^2+4x-3-\left(2x^2+4x-3\right)

-\left(2x^2+4x-3\right):\quad -2x^2-4x+3

=2x^2+4x-3-2x^2-4x+3

\mathrm{Simplify}\:2x^2+4x-3-2x^2-4x+3:\quad 0

=0

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Answer:

3 outcomes

Step-by-step explanation:

question asks only 1 head therefore THT, TTH, HTT

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2 years ago
PLEASE HELP!!!!<br> -1 3/5 divided by (-2/3)<br> Write the answer as a mixed number
natka813 [3]

Answer:

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5 0
3 years ago
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solniwko [45]
1836 you just multiply 34 x 54
4 0
3 years ago
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I need HELPPPP I'll mark you the brainliest!
maksim [4K]

B, x = 2

Step-by-step explanation:

Given the vertices of the image, and preimage of this right isosceles triangle, we can find the line of reflection by definitively understanding how reflections work. Given the preimage contains the points A(-1,1), B(1,-1), and C(-3,-1). And that the image contains the points A'(5,1), B'(3,-1), C'(7,-1). We can differentiate the corresponding points and apply them to the rules of a reflection. if figure Z is reflected over x = n,

than Z'(x,y) = Z(-x+2n,y). Logically, you can see that this pattern resembles all three coordinates for the transformation. i.e A'(5,1) = A(--1+2n,1) ; (1+2n,1) = (5,1) ; 1 + 2n = 5, 2n = 4, n = 2

we can prove this by using another point:

B'(3,-1) = (-1+2n,-1) = (-1 + 4, -1) = (3,-1)

Hopefully you understand,

<u>Pls mark brainliest this took me a very long time.</u>

3 0
2 years ago
Simplify the expression(a4−6a2b2+ b4)−(−2a4+5a2b2+ 3b4) and hence, find its value for a = 2and b = −1.
ELEN [110]

Answer:

(a) 3a^4 - 11a^2b^2 -2b^4

(b) 3a^4 - 11a^2b^2 -2b^4= 2

Step-by-step explanation:

Given

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Solving (a): Simplify

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Open brackets

a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4

Collect Like Terms

a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4

Simplify Like Terms

3a^4 - 11a^2b^2 -2b^4

Solving (b): Simplify when a = 2 and b = -1

3a^4 - 11a^2b^2 -2b^4

3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4

3 * 16 - 11 * 4 * 1 - 2 * 1

48 - 44 - 2

= 2

Hence:

3a^4 - 11a^2b^2 -2b^4= 2

4 0
2 years ago
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