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Damm [24]
4 years ago
15

Write the product in simplest form: -8w * (-w)

Mathematics
1 answer:
Hitman42 [59]4 years ago
7 0
8w

-8w times -w is like -8*-1 which would just make the number positive.
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Ellen flipped a coin 80 times. The coin landed heads up 44 times and tails up 36 times. Compare the theoretical and experimental
devlian [24]

Given:

Ellen flipped a coin 80 times. The coin landed heads up 44 times and tails up 36 times.

To find:

The theoretical and experimental probabilities of the coin landing tails up and compare them.

Solution:

We know that, the coin landed either heads up or tails up. So, the theoretical probabilities of the coin landing tails up is

P(T)=\dfrac{Tails}{Total}

P(T)=\dfrac{1}{2}

P(T)=0.5

Ellen flipped a coin 80 times. The coin landed heads up 44 times and tails up 36 times.

Total = 80

Tails =36

The experimental probabilities of the coin landing tails up is

P(T)=\dfrac{Tails}{Total}

P(T)=\dfrac{36}{80}

P(T)=0.45

Therefore, the theoretical and experimental probabilities of the coin landing tails up are 0.5 and 0.45 respectively. The theoretical probability is greater than the experimental probability.

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3 years ago
How do you change a decimal into a percent
fgiga [73]

Answer:

move the decimal to the left twice

Step-by-step explanation:

3 0
3 years ago
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At Trent's garage, 3 cases of brake fluid last 4 weeks. Trent has 5 cases. How much more brake fluid should Trent order so that
Ivan
3 cases / 4 weeks = 0.75 cases per week

for 13 weeks = (0.75 * 13) = 9.75 cases

9.75 - 5 = 4.75 rounded = 5...he needs to order 5 cases
4 0
4 years ago
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Kate bought 4 cans of soup for $2.67. How much would it cost for her to buy 10 cans?
gavmur [86]

Answer:

It would be 6.60

Step-by-step explanation:

first you have to find the price of one can, so you divided 2.67 by 4.

the answer would actually be 0.6675, but you have to stop at the tenths place for money, so in this case, it would be 0.66.

we multiply 0.66 by 10 and get 6.6 which is also 6.60

It would cost $6.60 to but 10 cans.

Idk if this helps, but I hope it does.

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Answer:

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