For the given graph , slope of the line is equal to ( 1 / 2 ).
As given in the question,
Form the given graph,
Scale is given by,
On x-axis each unit of the graph represent 1 unit.
On y- axis each unit of the graph represent 1 unit.
Consider two coordinates from the line of the graph,
( x₁ , y₁ ) = ( 1, 2 )
( x₂ , y₂ ) = ( 3, 3 )
Slope of the line = ( y₂ - y₁ ) / ( x₂ - x₁ )
Substitute the value in the formula of the slope we get,
Slope of the line = ( 3 - 2 ) / ( 3 - 1 )
⇒ Slope of the line = 1 / 2
Therefore, for the given graph , slope of the line is equal to ( 1 / 2 ).
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If the width is Wthen the length is 2W-5 W(2W-5)=422W2-5W = 422W2-5W-42 = 0 Factor by grouping or do the quadratic equation.Multiply the coefficient of the squared term.. 2..by the constant ..-42.. 2(-42)=-84Factors of -84 that add to the coefficient..-5.. ofthe W term are 7(-12)Replace the -5W with -12W + 7W 2W2-12W+7W-42 = 02W(W-6) + 7(W-6)=0(2W+7)(W-6)=0
Either: 2W+7 = 0 or W-6 = 0 2W = -7 W = 6 cm W = -7/2 cm
Since W will not be a negative, our width is 6cmThe length is 2W-5 = 2(6)-5=12-5 = 7 cm
0.9 is the answer hope it helps.
The function given is a composite function. Let's work from the outside in:
First step:
![\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5By%5D%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bln%28sinh%282x%29%29%5D)
Now, let's work it out:
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * \frac{d}{dx}[sinh(2x)]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%5Cfrac%7B1%7D%7Bsinh%282x%29%20%7D%20%2A%20%20%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bsinh%282x%29%5D)
Next step:
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) * \frac{d}{dx}[2x]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%5Cfrac%7B1%7D%7Bsinh%282x%29%20%7D%20%2A%20cosh%282x%29%20%2A%20%20%5Cfrac%7Bd%7D%7Bdx%7D%5B2x%5D%20)
Next step:
Simplify:
Simplify further:
Remember that:
So,
your final answer is:
So, your answer is
C. Hope I could help you!
