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Archy [21]
3 years ago
6

Food travels directly from the stomach to the

Chemistry
1 answer:
OleMash [197]3 years ago
3 0
From the stomach, the food travels to the small intestine. This happens with the help of a movement known as peristalsis. Juices are released in the small intestine, which helps in the breakdown of carbohydrates, starch, and proteins. 
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Can someone help me with this
lord [1]

Answer: A

Explanation:

8 0
3 years ago
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Which of the following is true about Oxygen (O), Sulfur (S) and Neon (Ne)? (Choose 3)
devlian [24]

Answer:

from the way I understand the question I think the answer is (B)

Explanation:

Because the distribution into shells of oxygen is 2,6 and in sulfur is 2,8,6 and oxygen has a 8th number of electrons and sulfur has the 16th number of electrons

3 0
3 years ago
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How to prepared sodium chloride solution.​
nexus9112 [7]

Explanation:

Dissolve 93.52g of NaCl in about 400mL of distilled water, then add more water until final volume is 800mL. If starting with a solution or liquid reagent: When diluting more concentrated solutions, decide what volume(V2) and molarity (M2) the final soluble should be.

4 0
3 years ago
A 1.000 g sample of an unknown hydrate of cobalt chloride is gently dehydrated. The resulting mass is 0.546 g. The cobalt is iso
ira [324]

Answer:

Explanation:

From the 1 g sample you have:

0.546 grams of cobalt chloride

1-0.546=0.454 grams of water

Now:

1) The salt

Of the 0.546 g, 0.248 g are cobalt (Mr=58.9) and the rest id Cl (Mr=35.45):

n_{Co}=\frac{0.248 g}{58.9 g/mol}=4.21*10^{-3}mol

n_{Cl}=\frac{0.298 g}{35.45g/mol}=8.4*10^{-3}mol

Dividing:

\frac{n_{Cl}}{n_{Co}}=\frac{8.4*10^{-3}mol}{4.21*10^{-3}mol}=2

So the molecular formula will be:

CoCl_2

2) The water

The water's molecular weight is M=18 :

n_{w}=\frac{0.454g}{18g/mol}=0.025 mol

Bonding with the Co:

\frac{n_{w}}{n_{Co}}=\frac{0.025mol}{4.21*10^{-3}mol}=6

The complete formula of the hydrate:

CoCl_2*6 H_2O

8 0
4 years ago
when methane reacts with oxygen, the products are carbon dioxide and water. How many grams of carbon dilxide are formed if 30 g
Wittaler [7]

Answer:

CH4+2O2→CO2+2H2O

Moles of oxygen=3232=1

Moles of carbon dioxide=4422=0.5

Moles of water=1818=1

1 mole of methane reacts with 2 moles of oxygen to give 1 mole of CO2 and 2 moles of water so 0.5 mole of methane will be required which is equal to 0.5×16=8g.

Explanation:

8g

4 0
2 years ago
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