Answer:
A. Arginine
Explanation:
The urea cycle is the cycle of the biochemical reactions which produces urea from ammonia.
Steps of the urea cycle:
- Carbamoyl phosphate, in presence of ornithine transcarbamoylase is converted to citrulline by the denotation of carbamoyl phosphate groupto ornithine and a phosphate group is released.
- Amino group of the aspartate and carbonyl group of the citrulline are condensed to form argininosuccinate in the presence of enzyme, argininosuccinate synthetase. This condensation reaction is ATP dependent.
- <u>Argininosuccinate then undergoes cleavage by the argininosuccinase to form intermediate, arginine and fumarate.</u>
- <u>Arginine is then cleaved by the arginase to form urea as well as ornithine.</u> Ornithine is transported back to mitochondria to begin urea cycle again.
Answer: ≈ 67.4 g
Explanation:
A(t) = amount remaining in t years = A0ekt, where A0 is the initial amount and k is a constant to be determined. Since A(1690) = (1/2)A0 and A0 = 80, we have 40 = 80e1690k 1/2 = e1690k ln(1/2) = 1690k k = -0.0004 So, A(t) = 80e-0.0004t Therefore, A(430) = 80e-0.0004(430) = 80e-0.172 ≈ 67.4 g
The answer to this question would be: too low
Molar mass would be determined by the number of mol and the mass of the object. Mass wouldn't be influenced by the temperature, but number of mol is. Using ideal gas formula of PV=nRT you can conlude that the amount of mol(n) is inversely related to the temperature (T).
If the temperature is higher than it supposed to be, then the amount of mol would be lower than it supposed to be.
1) The mass of 1 mole of virus is
2) There are 5.6 moles of viruses in an oil tanker
Explanation:
1)
One mole of a substance is the amount of that substance containing a number of particles equal to the Avogadro number:
This means that 1 mole of this virus should contain a number of virus particles equal to .
We know that the mass of 1 virus particle is
Therefore, the mass of 1 moles of viruses is equal to the mass of a single virus particle multiplied by the number of virus particles in one mole, :
2)
In this problem, we have that the mass of the oil tanker is
We also know that the mass of one mole of virus is
Therefore, we can find how many moles of viruses have a mass equal to the mass of the oil tanker by dividing the mass of the oil tanker by the mass of 1 mole of virus particles.
Mathematically, this is done by the following operation:
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D = m / V
D = 2790 g / 205 mL
D = 13.60 g/mL