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Sladkaya [172]
3 years ago
10

What is the relationship between mole, Avogadro number and mass?

Chemistry
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

The mass of one mole of a substance is equal to that substance's molecular weight. ... water is 18.015 atomic mass units (amu), so one mole of water weight 18.015 grams. ... Avogadro's number is a proportion that relates molar mass on an atomic ... one molecule of water (H2O), one mole of oxygen (6.022×1023 of O atoms)

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Which of the following statements is false concerning the formula of a compound?
aalyn [17]

Answer:

B. The number of atoms in a molecular formula is always greater than the number of atoms in an empirical  formula.

Explanation:

It is not always true that the number of atoms in a molecular formula is always greater than the number of atoms in an empirical formula.

The chemical formulae of a compound are of two main types;

  • The empirical formula is that which expresses the composition of a compound in the simplest whole number ratio.
  • The molecular formula shows the actual ratio of the atoms in a compound.

Sometimes the number of atoms in the molecular and empirical formula can be the same.

Also, the number of atoms in the molecular formula is always greater than that of the empirical formula when they are not the same.

3 0
3 years ago
How can I find the answer for this ?
12345 [234]
For what? what is your question 
7 0
3 years ago
What is the molar mass of AgF. 51.9g/mol 198.8g/mol 126.87g/mol 99.7g/mol
lisov135 [29]
Just find Ag and F on periodic table, find g/mol for each one and add them together
3 0
3 years ago
Calculate the mass of magnesium oxide formed when 3.0 grams of magnesium reacts with excess oxygen.
BlackZzzverrR [31]
Mg+O2=MgO
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3 0
3 years ago
If 1.9 kJ of heat is transferred to 96 g aluminum at 113°C, what would the
erastova [34]

Answer:

T2 = 135.1°C

Explanation:

Given data:

Mass of water = 96 g

Initial temperature = 113°C

Final temperature = ?

Amount of energy transfer = 1.9 Kj (1.9×1000 = 1900 j)

Specific heat capacity of aluminium = 0.897 j/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

Q = m.c. ΔT

1900 j = 96 g × 0.897 j/g.°C × T2 - 113°C

1900 j = 86.112 j/°C × T2 - 113°C

1900 j / 86.112 j/°C = T2 - 113°C

22.1°C + 113°C =  T2

T2 = 135.1°C

4 0
3 years ago
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