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2 years ago

Is P2I4 or Diphosphorus tetraiodide covalent or ionic?

Chemistry

2 answers:

Afina-wow [57]2 years ago

6 0

Answer: covalent bond.

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

As $P_2I_4$ or Diphosphorus tetraiodide is made up of phosphorous and iodine which are both non metals , it is a covalent bond.

elena55 [62]2 years ago

5 0

Diphosphorus tetraiodide is a covalent compound.

It has low melting point as compared to ionic compounds

It is a rare compound where the oxidation state of Phosphorous is +2.

It is also termed as subhalide of phosphorous.

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2 years ago

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How many significant figures are in the following number? 5.67 x 106<br> 3<br> 4<br> 5<br> 6

mixas84 [53]

3 these are 5,6&7 are the significant

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2 years ago

Can someone help me please :)

Fudgin [204]

I think it’s the third option but I’m not entirely sure

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2 years ago

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If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution

$\Delta T^o$ = freezing point of water

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$w_b$ = mass of solute

$w_a$ = mass of solvent

$M_b$ = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

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2 years ago