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Anestetic [448]
3 years ago
15

How would a disease that damages the nucleus most directly affect the functioning of cells?

Chemistry
1 answer:
RSB [31]3 years ago
3 0

Answer:

Hereditary information in the cell would be destroyed.

Explanation:

The nucleus can be defined as a membrane bound organelle that is found in eukaryotic cells. The main function of the nucleus is that it controls all activities that is related to the growth of the cell and also reproduction. The nucleus contains the cell hereditary information(DNA).

The nucleus is the most important organelle in the cell, It can sometimes be referred to as the brain of the cell. Therefore any health related condition that affects the nucleus would directly destroy all hereditary information that is stored in the cell.

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To compare how different types of soil absorbed water, Christian set up an experiment. He poked equal numbers and sizes of holes
lilavasa [31]

Answer:

The empty cup

Explanation:

Got it right on the test

3 0
4 years ago
The process in which an atom or molecule loses one or more electrons to another atom or molecule is known as ________ .
Inga [223]

Answer:

Oxidation process

Explanation:

Oxidation is the transfer of electrons from an atom, molecule, or ion to another atom, molecule, or ion in a chemical reaction.

Oxidation is said to have taken place when the oxidation status of a atom, molecule, or ion is increases.

Oxidation process is said to include

Addition of oxygen atom or Electronegative atoms to another atom, molecule, or ion

Loss of one or more electrons by a atom, molecule, or ion

Increase in the oxidation number of a atom, molecule, or ion

Loss of a hydrogen or Electropositive atoms

5 0
4 years ago
To convert from liters/second to cubic gallons/minute, multiply the number of liters/second by 15.850 0 0.0353 00.2642 0 60
ivanzaharov [21]

Answer: 15.850

Explanation:

The conversion used from liters to gallons is:

1 L = 0.264172 gallon

The conversion used from sec to min is:

60 sec = 1 min

1 sec =\frac{1}{60}\times 1=0.017min

We are asked: liters/sec = gallons/min

liters/sec=\frac{0.264172}{0.017}=15.850gallons/min

Therefore, to convert from liters/second to gallons/minute, multiply the number of liters/second by 15.850.

8 0
4 years ago
A silver cube with an edge length of 2.38 cm and a gold cube with an edge length of 2.79 cm are both heated to 81.9 ∘C and place
never [62]

Answer:

The final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

Explanation:

<u>Given data;</u>

edge length of silver, a = 2.38 cm = 0.0238 m

edge length of gold, a = 2.79 cm = 0.0279 m

final temperature of silver, t = 81.9 ° C

final temperature of Gold, t = 81.9 ° C

initial temperature of water, t = 19.6 ° C

volume of water, v =  109.5 mL = 0.0001095 m³

<u>Known data:</u>

density gold 19300 kg/m³

density silver 10490 kg/m³

density water 1000 kg/m³

specific heat gold is 129 J/kgC

specific heat silver is 240 J/kgC

specific heat water is 4200 J/kgC

<u>Calculated data</u>

Apply Pythagoras theorem to determine the side of each cube;

Silver cube;

let L be the side of the silver cube

Taking the cross section of the cube (form a right angled triangle), the edge  length forms the <em>hypotenuse side</em>.

L² + L² = 0.0238²

2L² = 0.0238²

L² = 0.0238² / 2

L² = 0.00028322

L = √0.00028322

L = 0.0168

Volume of cube = L³

Volume of the silver cube = (0.0168)³ = 4.742 x 10⁻⁶ m³

Gold cube;

let L be the side of the gold cube

L² + L² = 0.0279²

2L² = 0.0279²

L² = 0.0279² / 2

L² = 0.0003892

L = √0.0003892

L = 0.0197

Volume of cube = L³

Volume of the silver cube = (0.0197)³ = 7.645 x 10⁻⁶ m³

Mass of silver cube;

density = mass / volume

mass = density x volume

mass of silver cube = 10490 (kg/m³) x 4.742 x 10⁻⁶ (m³) = 0.0497 kg

Mass of Gold cube

mass of gold cube = 19300 (kg/m³) x 7.645 x 10⁻⁶ (m³) = 0.148 kg

Mass of water

mass of water = 1000 (kg/m³) x 0.0001095 (m³) = 0.1095 kg

Let the heat gained by cold water be  Q₁

Let the heat lost  by silver cube = Q₂

Let the heat lost  by gold cube = Q₃

Let the final temperature of water = T

Q₁  = 0.1095 kg x 4200 J/kgC x (T–19.6)

Q₂ = 0.0497 kg x 240 J/kgC x (81.9–T)

Q₃ = 0.148 kg x 129 J/kgC x (81.9–T)

At thermal equilibrium;

Q₁ = Q₂ + Q₃

0.1095 x 4200  (T–19.6)  = 0.0497 x 240 x (81.9–T)  + 0.148 x 129 x (81.9–T)

459.9 (T–19.6) = 11.928 (81.9–T) + 19.092(81.9–T)

459.9T - 9014.04 = 976.9032 - 11.928T + 1563.6348 - 19.092T

459.9T + 11.928T + 19.092T = 9014.04  + 976.9032 + 1563.6348

490.92T = 11554.578

T = 11554.578 / 490.92

T = 23.54 ⁰C

Therefore, the final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

6 0
3 years ago
Which of the following would be appropriate reason(s) for scientists to reject atomic theory?​
leonid [27]
It posed a contradiction to Quantum Theory
3 0
3 years ago
Read 2 more answers
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