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PtichkaEL [24]
3 years ago
12

I need help so please help me

Chemistry
1 answer:
Kay [80]3 years ago
3 0

Answer:b

Explanation:

I honestly don’t know if this I right but that would be my guess

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What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Fantom [35]

it has a density 6.50, hope it help

3 0
3 years ago
mickey reacts magnesium with 1.0 M of hydrochloric acid. the reaction tales 2 minutes and 34 seconds to complete. what are 2 way
lutik1710 [3]

Answer:

Explanation:

To slow down this reaction, we can use any of the methods listed below:

  • Increase the size of the magnesium by using solid lumps of  the metal. This will take a much faster time to react than powered and granulated magnesium.
  • Reduce the concentration of the acid.
  • Let the reaction take place at a much lower temperature than that given.

These conditions will slow down a chemical reaction.

7 0
3 years ago
You have a solid 7.00 gram mixture of sodium nitrate and silver nitrate. You add distilled water to dissolve the solids. Now you
olganol [36]

Answer:

Net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

44.9% as AgNO₃

Explanation:

When sodium nitrate, NaNO₃ and silver nitrate, AgNO₃ are dissolved in water, the Na⁺, NO₃⁻ and Ag⁺ ions are formed.

Then, the addition of NaCl (Na⁺ and Cl⁻) produce AgCl⁻ as precipitate. <em>The net ionic equation is:</em>

<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 />

If 2.54g of AgCl are formed and represents the 95.9% of yield. The real amount of AgCl is:

2.54g AgCl * (100% / 95.9%) = 2.65g AgCl.

In moles (Molar mass AgCl = 143.32g/mol):

2.65g AgCl * (1mol / 143.32g) = 0.0185 moles of AgCl = Moles of AgNO₃

<em>Because all Ag comes from AgNO₃</em>

<em />

Thus, the original mass of silver nitrate and its precentage is (Molar mass AgNO₃ = 169.87g/mol):

0.0185 moles AgNO₃ * (169.87g / mol) = 3.14g of AgNO₃

Percentage:

3.14g AgNO₃ / 7.00g * 100 =  

<h3>44.9% as AgNO₃</h3>
3 0
3 years ago
In the 1700s and 1800s. royalty in Europe often married their close relatives: furthermore, recessive genetic diseases such as h
satela [25.4K]

Answer:

Hi

Inbreeding increases the chances of transmission to the next generation of types of inherited diseases. Our genome is made up of two copies of each gene, one inherited from our father and one from our mother. In order for autosomal recessive diseases to be found, the two copies of the gene need to be mutated. If only one of the copies is mutated and the other is not, the person is a carrier but does not manifest any of the clinical symptoms of the disease. One of these diseases is hemophilia. An example of this is Prince Leopold, he was the first real member affected by hemophilia, in this case hemophilia B. When one of the proteins necessary for blood clotting is missing, the wounds take much longer to heal. Small cuts are not usually a problem, but major injuries can cause bleeding.

The defective gene in people who suffer from this type of hemophilia is called F9, and it is located on the X chromosome. That means it has an inheritance linked to sex. Women have two X chromosomes (XX), while men have an X chromosome and one Y (XY). Since hemophilia alleles are recessive, two defective alleles are needed in women to suffer from the disease, while only one is needed in men. Therefore, the disease is much more common in men. The most frequent hemophilia is that of type A and is due to a defect in coagulation factor VIII, whose gene also has an inheritance linked to sex.

Explanation:

4 0
3 years ago
A laser is emitting photons with a wavelength of 639.8 nm. What is the energy for 1 mole of these photons? For Planck's constant
PSYCHO15rus [73]

Answer:

The energy for 1 mole of these photons is E = 31 × 10^{-23} \frac{KJ}{mol}  

Explanation:

Given data

Wavelength \lambda = 639.8 × 10^{-9} m

Plank constant h = 6.626 × 10^{-34} J sec

Speed of light c = 3 × 10^{8} meter per second

We know that Energy  of a photon is given by

E = \frac{h c}{\lambda}

Value of ( h c ) = 6.626 × 10^{-34}  × 3 × 10^{8} = 19.878 × 10^{-26}

\lambda = 639.8 × 10^{-9} m

Now Energy  of a photon

E =( \frac{19.878}{639.8}) 10^{-17}

E = 0.031 × 10^{-17} Joule per mole

E = 31 × 10^{-23} \frac{KJ}{mol}  

Therefore the energy for 1 mole of these photons is E = 31 × 10^{-23} \frac{KJ}{mol}  

4 0
4 years ago
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