Answer:
Determining how many ozone molecules are lost in the atmosphere.
Explanation:
Because if you change two things then you do not know which one has affected or altered the dependent variable. if you only change one then you know what exactly changed and why
- The water in the pot becomes hotter as a result of heat transfer.
- <em>Energy can be transferred from a region to another , but there will still the same overall amount of energy</em> ( energy conservation)
- When a pot containing water is placed on the stove and heat is applied with the burner, there is a flow of heat from the burner to the water.
- Heat will be transferred from the burner to the pot, then there will be transferred of heat from the pot to the water, the molecules there in the water will be energized as a result of the heat transfer until the boiling point is reached.
- Energy transfer can take place in three form, this could be conduction, radiation or convention.
- Convention which is a cyclical process is the one that occurs in fluids only so as a result of convection , the water at the bottom will be heated and the molecules start moving and it will rise till it get to the water at the top of the pot.
<em>Therefore, the water is heated as a result of heat transfer.</em>
<em />
Learn more at : brainly.com/question/17858145?referrer=searchResults
For an element whose third shell contains six electrons, the appropriate electron configuration is; 1s2 2s2 2p6 3s2 3p4.
The electron configuration shows the distribution of electrons in the shells of an atom and in orbitals.
We have been told that the six electrons are found in the third shell. This shell has n=3 and the configuration of this shell must ns2 np4.
The only electron configuration that meets this standard is 1s2 2s2 2p6 3s2 3p4.
Learn more: brainly.com/question/18704022
F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>
