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3 years ago

How would the galaxy be different if gravity did not exist

Chemistry

1 answer:

kozerog [31]3 years ago

5 0

Answer:

because the voidness of the air can trigger a catastrophic disaster for the galaxy

Explanation:

than you so much

good luck

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The first law of thermodynamics is observed when

krek1111 [17]

Answer:

Explanation:

The first law of Thermodynamics is known as Conservation because it explains that energy is always maintained within a closed system and cannot be created or destroyed. Therefore, this is observed when there is no longer change in temperature in a system. Mainly because the energy is not being transferred to and from another system. Without this transfer of energy, the energy itself gets conserved within the system and the temperature no longer fluctuates.

8 0

2 years ago

Which of the following samples would be the most compressible?

Andrej [43]

Answer:

CO2 (g)

Explanation:

In solids the interatomic or intermolecular space is least . It is most pronounced in gases . That is why inter molecular or interatomic attraction is least in gases . That is why gas flows .

Hence , when we try to compress a gas , due to inter molecular space , it is most likely to get compressed . It will be least compressed when we try to compress a solid because of lack of intermolecular space .

7 0

2 years ago

Write the oxidation and reduction half reactions;

luda_lava [24]

Answer:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

$Br_2+2e^-$ ⇒ $2Br^-$

$Mg$ ⇒ $Mg^{2+}+2e^-$

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

Explanation:

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

$Br_2+2e^-$ ⇒ $2Br^-$

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

$Mg$ ⇒ $Mg^{2+}+2e^-$

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

3 0

3 years ago

Read 2 more answers

What are the masses of the four different BrClBrCl molecules? Express the masses in atomic mass units using six significant figu

Sliva [168]

Answer ; The question is missing in some details, but here are he details ;

The two naturally occurring isotopes of bromine are

81Br (80.916 amu, 49.31%) and

79Br (78.918 amu, 50.69%).

The two naturally occurring isotopes of chlorine are

37Cl (36.966 amu, 24.23%) and

35Cl (34.969 amu, 75.77%).

Bromine and chlorine combine to form bromine monochloride, BrCl.

Explanation:

The detaile calculation is as shown in the attachment.

6 0

3 years ago

Calculate the mass in grams for each of the following liquids.

WITCHER [35]

The density is calculated as mass per volume, so if we want to solve for mass, we would multiply density by volume.
For Part A: if we have a density of 0.69 g/mL, and a volume of 280 mL, multiplying these will give a mass of: (0.69 g/mL)(280 mL) = 193.2 g. Rounded to 2 significant figures, this is 190 g gasoline.
For Part B: if we have a density of 0.79 g/mL, and a volume of 190 mL, multiplying these will give a mass of: (0.79 g/mL)(190 mL) = 150.1 g. Rounded to 2 significant figures, this is equal to 150 g ethanol.

3 0

3 years ago