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3241004551 [841]
3 years ago
13

The need for energy, gained by respiration and photosynthesis, is the driving force of the oxygen cycle. Please select the best

answer from the choices provided T F
Chemistry
2 answers:
eimsori [14]3 years ago
8 0

Answer: True

Explanation: Oxygen cycle is the process by which oxygen is released into the atmosphere by photosynthesis and is used by aerobic organisms while the carbon dioxide is released as a by product of respiration. This carbon dioxide is used in photosynthesis for production of glucose.

6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2

Hence, for oxygen to remain in the atmosphere, it has to circulate through various forms of nature and this circulation of oxygen is called as oxygen cycle.

MariettaO [177]3 years ago
5 0
The answer is T - true.
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A beaker contains a 25 mL solution of an unknown monoprotic acid that reacts in a 1:1 stochiometric ratio with NaOH. Titrate the
Luden [163]

Answer:

concentration of HCL = 4.56 g/dm3

Explanation:

If the titrant and analyte have a 1:1 mole ratio, the formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base. (Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution.)

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 = \frac{\textup{amount~of~solute~in~mol}}{\textup{volume~in~dm}^3}

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 = \frac{\textup{amount~of~solute~in~mol}}{\textup{volume~in~dm}^3}

Concentration in mol/dm3 = \frac{\textup{0.00250}}{\textup{0.0200}}

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

8 0
2 years ago
Explain what happens when a cold air mass overtakes a warm air mass?
SVEN [57.7K]
Is this a multiple answer?
6 0
2 years ago
1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)<br> weigh?
Nimfa-mama [501]

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

7 0
3 years ago
How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

8 0
3 years ago
Molecules are different from atoms because they
tatyana61 [14]
D) Contain Chemical bonds.
5 0
3 years ago
Read 2 more answers
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