Answer:
i) 16 mL of ethanol
ii) maximum amount recoverable = 15.52 g; percentage recovery = 97%
iii) maximum amount recoverable = 15.1 g
percentage recovery = 94.4%
Explanation:
Solubility = mass/volume
i) mass of ethanol recovered per mL of ethanol when cooled from 78 °C to 0 °C = 0.13 - 0.03 = 0.10 g
Therefore 1.60 g of Y will require a minimum of 1.60 x 1 mL/0.10 g = 16 mL of ethanol
ii) maximum amount of Y that can be recovered is given as :
mass of Y left in solution after recrystallization, x is obtained
0.03 g/mL = x g/16 mL
x = 0.48 g
maximum amount recoverable = 16 - 0.48 = 15.52 g
percentage recovery = (15.52/16) x 100 % = 97%
iii) if 30 mL of ethanol were used:
mass of Y left in solution after recrystallization, x is obtained;
0.03 g/mL = x g/30 mL
x = 0.03 x 30 = 0.9 g
maximum amount recoverable = 16 - 0.9 = 15.1 g
percentage recovery = (15.1/16) x 100% = 94.4%
Sublevel 2s and 2p contains the valence electrons for nitrogen.
P(total)=P1+P2+P3+...
P(total)=P(N2)+P(others)+P(O2)
100kPa=78kPa+1kPa+P(O2)
P(O2)=100-79=21kPa
