Answer:
Follows are the solution to these question:
Explanation:
A simple gullible algorithm is present. Let h mark the house to the left. Then we put a base station about 4 kilometers to the right. Now delete and repeat all the houses protected by this base station. In this algorithm, they can simply be seen to position baselines at b1, . . , bk as well as other algorithms (which may be an optimum algorithm) at 
and so on. (from left to right) 
That's why 
.
Well the nonchalant question given for 4th grade red named babyface Justin and Jerome
Answer:
5) 3 0 0
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.
So value at index 1 would be = val[1] = 0
The term i++ is incrementing the value of i, it makes i =2
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.
So value at index 2 would be = val[2] = 0
Hence, the output would be {3 0 0}. So 5th option is correct.
It follows the normal convention of BODMAS , which is the order of precedence of operations , so the answer equals to 26
