Ask question

Ask question

All categories

3 years ago

12

Molecule Energy Released

2 answers:

charle [14.2K]3 years ago

4 0

Carbohydrate; contains a low ratio of oxygen atoms.

Vitek1552 [10]3 years ago

4 0

fats contian a low raito of oxgen atoms

You might be interested in

Describe how electron arrangements are given using electron configurations.

emmainna [20.7K]

According to the principle, electrons fill orbitals starting at the lowest available energy states before filling higher states (e.g., 1s before 2s). The Madelung energy ordering rule: Order in which orbitals are arranged by increasing energy according to the Madelung Rule.

hi

I hope u understand

3 0

3 years ago

I really need help on this one!!

Lady bird [3.3K]

Answer:

Due to the decrease in the gravitational force, it will take longer time for ball to reach the ground while dribbling. Moreover, the hang time of players will also be longer. This means that the players will stay on air longer and will be able to jump higher.

3 0

3 years ago

Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble

Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

$AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq)$ ............. (1)

$K_{sp}$ = $[Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}$

Reaction for the complex formation is as follows.

$Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq)$ ........... (2)

$K_{f}$ = $\frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}$

When we add both equations (1) and (2) then the resultant equation is as follows.

$AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$ ............. (3)

Therefore, equilibrium constant will be as follows.

K = $K_{f} \times K_{sp}$

= $1.0 \times 10^{8} \times 1.8 \times 10^{-10}$

= $1.8 \times 10^{-2}$

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of $NH_{3}$ for complexation. This means we have to set

$[Ag^{+}]$ = $[Cl^{-}]$

= $\frac{0.010 mol}{1 L}$

= 0.010 M

For the net reaction, $AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$

Initial : 0.010 x 0 0

Change : -0.010 -0.020 +0.010 +0.010

Equilibrium : 0 x - 0.020 0.010 0.010

Hence, the equilibrium constant expression for this is as follows.

K = $\frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}$

$1.8 \times 10^{-2}$ = $\frac{0.010 \times 0.010}{(x - 0.020)^{2}}$

x = 0.0945 mol

or, x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of $NH_{3}$ needed to be added is 0.095 mol.

3 0

4 years ago

Which of the following could be the pH of an extremely acid solution, such as that in a car battery?

Anna [14]

Explanation:

Acidic pH can be between 0 and 6. Hence the answer is D.

7 is neutral whereas 10 and 14 are basic.

3 0

3 years ago

Hows does one determine a molecular formula from the emprical formula?

Lynna [10]

Answer:

To determine a molecular formula from the empirical formula you need to know:

-the molecular mass

-calculate the empirical formula mass

-divide the molecular formular by the empirical formula mass

-multiply by this whole number the empirical formula

Explanation:

See the image below

3 0

3 years ago