Answer:
Stay in shade
Explanation:
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Answer:
A
-1440J
Explanation:
Hello,
This question requires us to calculate the work done on a object to move it from point A to point B
Data
Mass = 60kg
Initial velocity (V1) = 8.0m/s
Final velocity (V2) = 4.0m/s
Workdone on an object is equal to force applied on the object to move it through a particular distance.
Work done = force × distance
Force (F) = mass × acceleration
Distance = s
F = Ma
Work done = M× a × s
But a = velocity (v) / time (t)
Work done = mvs / t
But velocity = distance/ time
Work done = mv × v/
Work done = mv²
Work done = ½mv²
Workdone = ½M(V2² - V1²)
Workdone = ½ × 60 (4² - 8²)
Work done = 30 × (16 - 64)
Workdone = 30 × (-48)
Work done = -1440J
Work done = -1.44kJ
The workdone on the object is equal to -1.44kJ
<span>1s2 2s2 2p6 3s2 3p2, P (Phosphorous)1s2 2s2 2p6 3s2 3p3,S (Sulfur)1s2 2s2 2p6 3s2 3p4,Cl (Chlorine)1s2 2s2 2p6 3s2 3p5, Ar ( Argon)1s2 2s2 2p6 3s2.</span>
