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spin [16.1K]
3 years ago
11

What is the [H₃O⁺] (hydronium concentration) of an aqueous solution that has a pH of 3.30?

Chemistry
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

5.01 *10^(-4) M

Explanation:

pH = - log[H₃O⁺]

[H₃O⁺] = 10^(-pH)= 10^(-3.30) = 5.01 *10^(-4) M

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Consider the following reaction
Fynjy0 [20]

Answer:

92.72 kJ

Explanation:

2 N₂ (g) + O₂ (g) —-> 2 N₂O

According to question , one mole of N₂O requires 163.2 kJ of heat

Molecular weight of N₂O = 44 gm

25 g  N₂O = 25 / 44 mole

25 / 44 mole will require 163.2 x 25 / 44 kJ

= 92.72 kJ

6 0
2 years ago
How many grams are in 4 moles of aluminum phosphate
vladimir2022 [97]

Answer:

487.8116

Explanation:

4 0
3 years ago
Read 2 more answers
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
Can someone help me sort this :(
jeyben [28]

Answer: A. is prey B. is predator C. is habitat D. is comunity E. is plants are producers and plant eating animals  consumors  F. is food chain G. is food web H. parasite I decomposers and scavengers J. is compete K an adsption

Explanation:

7 0
2 years ago
Select the correct value for the indicated bond angle in each of the following compounds: O-S-O angle of SO2 F-B-F angle of BF3
Stels [109]

Answer:

(A) O-S-O bond angle of SO₂ molecule = 119°

(B) F-B-F bond angle of BF₃ molecule = 120°

(C) Cl-S-Cl bond angle of SCl₂ molecule = 103°

(D) O-C-O bond angle of CO₂ molecule = 180°

(E) F-P-F bond angle of PF₃ molecule = 96.3°

(F) H-C-H bond angle of CH₄ molecule = 109.5°

Explanation:

Bond angle refers to the angle between two adjacent chemical bonds in a molecule. The bond angle is different for different molecular geometry.

The Valence shell electron pair repulsion theory predicts the molecular geometry and shape of the given molecule by the number of lone pairs on central atom and number of atoms bonded to central atom.

(A) SO₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 1

<u>Therefore, the shape of SO₂ molecule is bent and the O-S-O bond angle is 119°.</u>

(B) BF₃ molecule

The number of atoms bonded to B = 3

Number of lone pairs on B = 0

<u>Therefore, the shape of BF₃ molecule is trigonal planar and the F-B-F bond angle is 120°.</u>

(C) SCl₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 2

<u>Therefore, the shape of SCl₂ molecule is bent and the Cl-S-Cl bond angle is 103°.</u>

(D) CO₂ molecule

The number of atoms bonded to C = 2

Number of lone pairs on C = 0

<u>Therefore, the shape of CO₂ molecule is linear and the O-C-O bond angle is 180°.</u>

(E) PF₃ molecule

The number of atoms bonded to P = 3

Number of lone pairs on P = 1

<u>Therefore, the shape of PF₃ molecule is trigonal pyramidal and the F-P-F bond angle is 96.3°.</u>

(F) CH₄ molecule

The number of atoms bonded to C = 4

Number of lone pairs on C = 0

<u>Therefore, the shape of CH₄ molecule is tetrahedral and the H-C-H bond angle is 109.5°.</u>

7 0
3 years ago
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