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3 years ago

Two side lengths of a triangle are 17 meters and 12 meter long. What is the range of possible lengths for the third side?

1 answer:

5 0

Use a^2+b^2=c^2.
so u might have two answer one if u plug 17 and 12 as your a and b and solve for c
second is when you plug 12 as a and 17 as 17 qnd solve for b.
hope this helped

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A relay race has 4 runners who run different parts of the race. There are 16

xz_007 [3.2K]

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3 years ago

AJ purchased a new TV for $1200. The regular price of the TV was $1500.what percent did AJ save buying it on sale ?

svet-max [94.6K]

A. 20%

Work: 1500 x .20 = 300

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Hope this helps!

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3 years ago

Find the area if the composite shape

soldi70 [24.7K]

Answer:

111 m²

Step-by-step explanation:

A rectangle is a quadrilateral (has four sides and four angle) with two pairs of parallel sides. Opposite sides of a rectangle are equal to each other. Also all the angles of a rectangle are 90° each.

The area of a rectangle = length * width

For rectangle 1, length = 12 m, width = 3 m

Therefore area of rectangle 1 = length * width = 12 m * 3 m = 36 m²

For rectangle 2, length =(12 m - 3 m - 3 m) = 6 m, width =(15 m - 10 m) =5 m

Therefore area of rectangle 2 = length * width = 6 m * 5 m = 30 m²

For rectangle 3, length = 15 m, width = 3 m

Therefore area of rectangle 3 = length * width = 15 m * 3 m = 45 m²

Area of composite shape = Area of rectangle 1 + Area of rectangle 2 + Area of rectangle 3

Area of composite shape = 36 m² + 30 m² + 45 m² = 111 m²

3 0

3 years ago

Please answer this correctly

Bond [772]

Answer: The second option (purple model)

Step-by-step explanation: It is that option because there were 80 toys collected which is 100% and then we do not what the 30% is.

5 0

3 years ago

Read 2 more answers

The 65 students in a classical music lecture class were polled, with the following results: 37 like Wolfgang Amadeus Mozart 36 l

Anna35 [415]

Answer:

a) 25

b) 30

c) 10

d) Not Mozart, 6

e) 2

Step-by-step explanation:

We use a Venn Diagram to solve this question.

I am going to say that:

A are the students who like Mozart.

B are the students who like Beethoven

C are the students who like Haydn.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those who only like Mozart, $(A \cap B)$ are those who like Mozart and Beethoven, $(A \cap C)$ are those who like Mozart and Haydn and $(A \cap B \cap C)$ are those who like all three of them.