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Radda [10]
3 years ago
13

A regular number cube is rolled. What is the probability that an odd number will not be rolled?

Mathematics
2 answers:
Dovator [93]3 years ago
7 0

Answer:

the answer is 5/6

Step-by-step explanation:

mixer [17]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

A regular die has 3 odd numbers (1, 3, and 5) and 3 even numbers (2, 4, and 6). The question asks for the probability that an odd number will not be rolled. This is the same as asking the probability of an even number being rolled. Since we have 6 numbers in our data set and 3 are even, we can deduce that 1/2 of them are even and the probability of an even number being rolled is 1/2.

HTH :)

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1^6 is just 1 so 1x=2, you can just take away the one because it is a given that if there is an x there is a 1, so the answer is x=2

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The robber stole only 32 pounds of quarters out of the coin machine. Quarters are weighed in ounces. If there are 16 ouncess in
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olga nikolaevna [1]

Answer:

50 % probability that the hat is blue.

Step-by-step explanation:

3 blue and 3 black = 6 total tickets

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According to Descartes rule what is a possible number of positive and negative roots
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Step-by-step explanation:

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2 years ago
The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than
k0ka [10]

Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

x + 5*y + 10*z = 227

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

y = z + 6\\x = 2 + 24*z

Applying these values on the first equation, we have:

2 + 24*z + 5*(z + 6) + 10*z = 227\\2 + 24*z + 5*z + 30 + 10*z = 227\\39*z + 32 = 227\\39*z = 227 - 32\\39*z = 195\\z = \frac{195}{39}\\z = 5

Applying z to the formulas of y and x, we have:

y = 5 + 6 = 11\\x = 2 + 24*5 = 122

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

4 0
3 years ago
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