<span>A quadratic equation of the form ax^2 + bx + c has a general solution of the form
x = - b +- b^2 - 4ac/2a
We shall use the expression under the radical in the formular method. The expression under the radical is called the discriminant.
If the discriminant D = b^2 - 4ac > 0 then the quadratic has two distinct real number solutions since the square root of any positive number is it self a positive number.
If D = b^2 - 4ac = 0 then we get expressions of the form (-b + 0) and (-b - 0). Regardless we end up with -b. This means when D = 0 we have one solution.
If D < 0 the quadratic equation has a conjugate pair of complex roots of the form a + bi</span>
Answer:
The answer to your question is x = -22; y = 4
Step-by-step explanation:
System of equations
2x + 5y = -24 ------------- l
3x - 5y = 14 ------------- ll
Process
1.- Multiply equation l equation l by 3 and equation ll by -2
6x + 15y = -72
-6x + 10y = -28 Add the equations
0 + 25y = 100
2.- Solve for y
y = 100/25
y = 4
3.- Substitute y in equation l to find x
2x + 5(4) = -24
Solve for x
2x + 20 = -24
2x = -24 - 20
2x = -44
x = -44/2
x = -22
B,
3/4-1/4=2/4
Line B ends on 2/4
Answer:
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Step-by-step explanation:
Answer:
1 2 5 . 6 9
1 2 5 . 6 7 0
125.69 Would be Greater.
Step-by-step explanation:
First number to the right of the decimal is the tenths place 2nd number would be hundredths and you'd increase etc.