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Rina8888 [55]
4 years ago
6

Determine the percent composition of all elements in enstatite, MgSiO3, a mineral found in Earth's crust.

Chemistry
2 answers:
kodGreya [7K]4 years ago
8 0
<span>Magnesium:
Mg molar mass: 24.3050
You have one atom of Mg so, <span>24.211% (mass percent)

</span></span><span>Silicon:
Si molar mass: 28.0855
You have one atom of Si so, <span>27.977% (mass percent)

</span></span><span>Oxygen:
O molar mass: 15.9994
You have three atoms so, <span>47.812% (mass percent)</span></span>
rusak2 [61]4 years ago
5 0

Explanation:

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100

Mass of magnesium atom = 24 g/mol

Mass of silicon atom = 28 g/mol

Mass of oxygen atom = 16 g/mol

Molar mass of MgSiO_3 =24 g/mol+28 g/mol+3 × 16 g/mol=100 g/mol

Composition of all elements in enstatite, MgSiO_3

Percentage of magnesium :

\frac{1\times 24 g/mol}{100 g/mol}\times 100=24\%

Percentage of silicon:

\frac{1\times 28 g/mol}{100 g/mol}\times 100=28\%

Percentage of oxygen:

\frac{3\times 16 g/mol}{100 g/mol}\times 100=48\%

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