Hi there!
1.
The period of a pendulum can be calculated using the following equation:
T = period (s)
L = length of string (m)
g = acceleration due to gravity (m/s²)
Plug in the values:
2.
Calculate the period:
Frequency is the reciprocal of the period, so:
Rolling of the eyes. The person is either vexed or frustrated.
Given: Mass m = 400 Kg; Height h = 3 m; g = 10 m/s²
Required: Work = ?
Formula: Work = Force x distance F = ma a = g F = mg
W = fd
W = mgh
W = (400 Kg)(10 m/s²)( 3 m)
W = 12,000 Kg.m²/s²
W = 12,000 J
The reactance of an inductor is given by:
X = 2πfL
X is the inductor's reactance
f is the frequency of the supplied voltage
L is the inductor's inductance
The given values are:
f = 60.0Hz
L = 43.8mH (I'm assuming the value is given in milli Henries because this is within the normal range of inductors)
Plug these values in and solve for X:
X = 2π(60.0)(43.8×10⁻³)
X = 16.512Ω
Round this value to 3 significant figures:
X = 16.5Ω
The relationship between AC voltage and current is given by:
V = IZ
V is the voltage
I is the current
Z is the impedance
For an AC inductor circuit, Z = X = 16.512Ω and V is the rms voltage 120V. Plug these values in to get the rms current:
120 = I×16.512
I = 7.2673A
Round this value to 3 significant figures:
I = 7.27A
1. To solve this problem, you must apply formula of Universal Gravitation Law, which is shown below:
F=Gm1m2/r²
F=2.75x10^-12
G=6.7x10^-11
r=2.6 m
m2=2m1
2. You must clear m1, as below:
F=G(m1)(2m1)/r²
F=G(2m1)²/r²
m1=√(Fr²/2G)
3. When you susbtitute the values into the formula m1=√(Fr²/2G), you obtain:
m1=√(Fr²/2G)
m1√0.13
m1=0.37
m2=2m1
m2=2(0.37)
m2=0.74
4. Therefore, the answer is:
m1=0.37
m2=0.74