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s2008m [1.1K]
3 years ago
15

Which one of the following acts is an example of body language?

Physics
2 answers:
Viktor [21]3 years ago
6 0
Rolling of the eyes. The person is either vexed or frustrated.
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

c. rolling of the eyes

Explanation:

(◔_◔)(◔_◔)(◔_◔)

You might be interested in
A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
eduard

Answer:

The x-component of the velocity is 16.07 m/s

The y-component of the velocity is 19.15 m/s

Explanation:

Given;

initial velocity of the football, u = 25 m/s

angle of projection, θ = 50⁰

The x-component of the velocity (horizontal component) is given as;

V_x = Vcos(50^0)\\\\V_x = 25 \ m/s \ \ \times \ \ 0.6428\\\\V_x = 16.07 \ m/s

The y-component of the velocity (vertical component) is given as;

V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s

7 0
3 years ago
How do I convert 498.82 cg to mg
mezya [45]
<span><u><em>Answer:</em></u>
498.82 cg is equivalent to 4988.2 mg

<u><em>Explanation:</em></u>
cg stands form centigrams
mg stands for milligrams

From the standards of conversion, to convert from centi to milli, we multiply the amount ny 10

<u>This means that:</u>
1 centigram = 10 milligram

To convert 498.82 cg to mg, all we have to do is <u>cross multiplication</u> as follows:
1 cg ..................> 10 mg
498.82 cg .........> ?? mg

498.82 cg = </span>\frac{498.82*10}{1}<span> = 4988.2 mg

Hope this helps :)</span>
3 0
4 years ago
Read 2 more answers
A charge of 50 µC is pushed by a force of 25 µN a distance of 15 m in an electric field. What is the electric potential differen
TiliK225 [7]
7.5 is the correct answer
8 0
3 years ago
Two lightbulbs work on a 120-V circuit One 50 W and the other is 100 W. Which bulb has a higher resistance? Explain pls!!!!
Sladkaya [172]

Answer:

Bulb 1 has more resistance.

Explanation:

Given that,

Two lightbulbs work on a 120-V circuit.

The power of circuit 1, P₁ = 50 W

The power of circuit 2, P₂ = 100 W

We need to find the bulb that has a higher resistance.

The power of the bulb is given by :

P = \dfrac{V^2}{R}

For bulb 1,

R_1=\dfrac{V^2}{P_1}\\\\R_1=\dfrac{(120)^2}{50}\\\\R_1=288\ \Omega

For bulb 2,

R_2=\dfrac{V^2}{P_2}\\\\R_2=\dfrac{(120)^2}{100}\\\\R_2=144\ \Omega

So, bulb 1 has higher resistance.

8 0
3 years ago
You can enter compound units that are combinations of other units that are multiplied together. to enter the ⋅ explicitly, type
alexdok [17]

Answer:

30 N \cdot m

Explanation:

The torque applied by a force can be calculated as

\tau = F d sin \theta

where

F is the magnitude of the force

d is the length of the arm

\theta is the angle between the direction of the force and the arm

In this problem, we have

F = 15 N

d = 2.0 m

\theta=90^{\circ}

Substituting into the equation, we find

\tau = (15)(2.0) sin 90^{\circ}=30 N \cdot m

7 0
3 years ago
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