Answer:
94.248 g/sec
Explanation:
For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:

And, the velocity of blood pumping is 30 cm^2
Now apply the following formula to solve the total current

Q = 94.248 g/sec
Basically we applied the above formula So, that the total current could come
My best guess would be:
"A force equal in magnitude but opposite in direction"
However I assume that this question is multiple choice, by the way it is introduced. Therefore it would be helpful if these options were also displayed - hence take this as my best guess only.
Answer:
a = 6.53 m/s^2
v = 11.5689 m/s
Explanation:
Given data:
engine power is 217 hp
70 % power reached to wheel
total mass ( car + driver) is 1530 kg
from the data given
2/3 rd of weight is over the wheel
w = 2/3rd mg
maximum force

we know that F = ma


the new power is 


solving for speed v

![v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}](https://tex.z-dn.net/?f=v%20%3D%200.7%20%5Cfrac%7B217%20%5B%5Cfrac%7B746%20w%7D%7B1%20hp%7D%5D%7D%7B1500%20%5Ctimes%206.53%7D)
v = 11.5689 m/s
Answer:
Explanation:
We Often solve the the integral neutron transport equation using the collision probability (CP) method which usually requires flat flux (FF) approach. In this research, it has been carried out in the cylindrical nuclear fuel cell with the spatial of mesh with quadratic flux approach. This simply means that the neutron flux at any region of the nuclear fuel cell is forced to follow the pattern of a quadratic function.
Furthermore The mechanism may be referred to as the process of non-flat flux (NFF) approach. The parameters that calculated in this study are the k-eff and the distribution of neutron flux. The result shows that all parameters are in accordance with the result of SRAC.
Answer:
The positions are 0.0194 m and - 0.0194 m.
Explanation:
Given;
amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m
speed of simple harmonic motion is given as;

the maximum speed of the simple harmonic motion is given as;

when the speed equal one fourth of its maximum speed


Thus, the positions are 0.0194 m and - 0.0194 m.