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hichkok12 [17]
3 years ago
9

_____ is the nonpersonal, paid communication a company places to influence consumer purchases.

Physics
1 answer:
GarryVolchara [31]3 years ago
6 0
Well publicity would be the socially accepted by standard prospect
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11). Determine the acceleration due to gravity if a 6kg book was on top of
DerKrebs [107]

Answer:

g = 9.8 [m/s²]

Explanation:

To solve this problem we must remember that the potential energy is defined as the product of mass by gravitational acceleration by the height or elevation with respect to a reference level.

Ep = m*g*h

where:

Ep = potential energy = 235.2 [J]

m = mass of the book = 6 [kg]

g = gravity acceleration [m/s²]

h = elevation = 4 [m]

Now replacing these values:

235.2 = 6*g*4

g = 235.2/(24)

g = 9.8 [m/s²]

6 0
3 years ago
When a person drinks an excessive amount of alcohol, that individual becomes drunk or intoxicated, a condition resulting in a la
Luba_88 [7]

Answer:by messing with the different organs and systems and causing damage them.

Explanation:

4 0
3 years ago
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What conclusions can be drawn about the existence of carbon-12, carbon-13, and carbon-14?
SashulF [63]
<span>These are isotopes of carbon and they all contain 6 protons and 6 electrons but each contains a difference number of neutrons - 6, 7, and 8 respectively.

^ This is the answer because an isotope changes the atomic mass, NOT atomic number. That means that the neutrons are changed, not the protons. </span>
7 0
3 years ago
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The International Space Station (ISS) orbits Earth in a nearly circular orbit that is 345 km above Earth's surface.
Tems11 [23]

Answer:

1) v = 7.70 10³ m/s , 2) F = 115 N and 3)    (F/W)% = 90.2%

Explanation:

1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal

    F = ma.

    F = G m M / r²

    a = v² / r

    G m M / r² = m v² / r

    G M / r = v²

Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth

    r = Re + 345 103

    r = 6.37 10⁶ + 3.45 10⁵

    r = 6.715 10⁶ m

Let's calculate the speed

   v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)

   v = 7.70 10³ m/s

The speed module is constant, so we can use the uniform motion relationships

   v = d / t

The distance is the length of the circle

   d = 2π r

   d = 2π 6.715 106

   d = 42.2 10⁶ m

Let's calculate the time

   t = d / v

   t = 42.2 10⁶ / 7.70 10³

   t = 5.48 10³ s

2) Let's use the universal gravitation equation

   F = G m M / r²

   F = 6.67 10⁻¹¹ 13.0  5.98 10²⁴ /(6.715 10⁶)²

   F = 11.5 10¹ N

   F = 115 N

3) in this for we are asked the relationship is out with the weight of the body on earth

   F / W = F / mg

   F / W = 115 / (13.0  9.8)

   F / W = 0.902

  F / W% = 90.2%

5 0
3 years ago
The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the i
Nadya [2.5K]
Mechanical advantage = ideal mechanical advantage x efficiency = 3.5 x 0.6 = 2.1
The mechanical advantage of the inclined plane is 2.1

7 0
3 years ago
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