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steposvetlana [31]
3 years ago
9

How do you find 1/2n+3<5

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

n < 1

Hope this helps! :)

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A chain weighs 8 pounds per foot. How many ounces will 5 inches weigh? Round your answer to the nearest tenth as needed.
Butoxors [25]

Given that a chain weighs 8 pounds per foot.

We to find the weight in ounces per 5 inches.

It is known that 1 foot is equal to 12 inches and 1 pound is equal to 16 ounces.

Given that the weight is 8 pounds per foot.

\begin{gathered} 8\text{pounds per foot}=8\text{ pounds per 12 inches} \\ =16\times8\text{ ounces per 12 inches} \\ =128\text{ ounces per 12 inches} \\ =10.6\text{ ounces per inch} \\ =10.6\times5\text{ ounces per 5 inches} \\ =53\text{ ounces per 5 inches} \end{gathered}

Thus, the answer is 53 ounces in 5 inches.

7 0
1 year ago
AYO HELP ME WITH THIS!!!!
xeze [42]

Answer:

a taco is 1.25 and a drink is 0.95

Step-by-step explanation:

tacos = t

drinks = d

5t + 3d = 9.10

3t + d = 4.70

this is a simultaneous equation so times the first one by one and the second by 3 and then take them away from each other and solving to get

t = 1.25 and d=0.95

one drink is $0.95

one taco is $1.25

Hope this helps!!

4 0
3 years ago
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
3 years ago
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}&#10;y=&2(&1x&-2)^2&-4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\&#10;\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\&#10;D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
Shayla is 5 feet tall and casts a shadow 2 feet long. at the same time, a nearby lamppost casts a shadow 8 feet long. write and
777dan777 [17]
Here is a proportion

5/2 = x/8

2x = 40
/2      /2

x = 20

Hope this helps
6 0
3 years ago
Read 2 more answers
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