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Taya2010 [7]
3 years ago
7

How are estuaries connected to oceanic organisms?

Chemistry
1 answer:
Viktor [21]3 years ago
5 0

Answer:

A: Estuaries provide a nursery grounds for oceanic organisms

Explanation:

the estuaries provide Ov2 and HvO2 for these organism

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If acid is splashed on your lab partner, immediately do which of the following?
amid [387]
Well really the right thing to do is find the nearest shower and rinse them off so I believe C. would be the best answer
5 0
3 years ago
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Calculate the mass of h2o and c6 h12 o6 required to make 250 gram of 40% solution of glucose
Sedaia [141]
40% solution of glucose is where the solution contains, by weight, 40% glucose and 60% water. 

Therefore, if the total weight of the solution is 250 g, 
mass of the glucose (C6H12O6) = 250 g * 40% = 100 g
mass of water (H2O) = 250 g * 60% = 150 g

Mass of water can also be calculated by subtracting the weight of glucose from the total weight of the solution:
mass of water = 250g-100g = 150g.
5 0
3 years ago
PLZZZZ HELPPPPPPPPPPPP<br><br> Which correctly describes molecule "a" in this diagram
pogonyaev

Answer is: adenosine triphosphate.

ATP is made of three components: the triphosphate (P), the sugar ribose and a nitrogenous base (adenine).

ATP is short for adenosine triphosphate

Adenosine triphosphate converts to either the adenosine diphosphate (ADP) or adenosine monophosphate (AMP), in this process energy is released.  

4 0
3 years ago
Read 2 more answers
3
IceJOKER [234]

Answer:

1. The balanced equation is given below:

C4H6O3 + H2O → 2C2H4O2

The coefficients are: 1, 1, 2

Explanation:

C4H6O3 + H2O → C2H4O2

The above equation can be balanced as follow:

There are 4 atoms of C on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of C2H4 O2 as shown below:

C4H6O3 + H2O → 2C2H4O2

Now, the equation is balanced as the number of atoms of the different elements present on both sides of the equation are equal.

The coefficients are: 1, 1, 2

5 0
2 years ago
A student prepares a 0.61mM aqueous solution of propionic acid C2H5CO2H. Calculate the fraction of propionic acid that is in the
MAXImum [283]

Answer:

The 13.76% of propionic acid is in the dissociated form in the solution

Explanation:

Concentration of propionic acid = c = 0.61mM = 0.61\times 10^{-3}M

mM=10^{-3}M

Degree of dissociation = α

C2H5CO2H\rightleftharpoons C2H5COO^-+H^+

At initial

c                             0   0

At equilibrium

c - cα                     cα   cα

The value of dissociation constant of propionic acid = K_a=1.34\times 10^{-5}

The expression of dissociation constant of propionic acid is given by :

K_a=\frac{c\times alpha c\times \alpha}{c(1-\alpha )}

K_a=\frac{c\alpha ^2}{(1-\alpha )}

1.34\times 10^{-5}=\frac{0.61\times 10^{-3}M\times \alpha ^2}{(1-\alpha )}

Solving the equation for \alpha:

\alpha =0.1376

\alpha=\frac{0.1376}{1}\times 100=13.76\%

The 13.76% of propionic acid is in the dissociated form in the solution

4 0
2 years ago
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