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lana [24]
3 years ago
9

A minimumenergy of 7.21x10-19 J is required to produce the photoelectric effect in chromium metal.

Chemistry
1 answer:
forsale [732]3 years ago
7 0

Answer:

<em>2.085 x 10^-20 J</em>

<em></em>

Explanation:

minimum energy required to produce photoelectric effect in chromium is given as hf =  7.21 x 10^-19 J

The work function of chromium Ф = 4.37 eV = 7.00151 x 10^-19 J

The minimum energy required to eject an electron from from a chromium metal E = ?

From E = hf - Ф

substituting values, we have

E = (7.21 x 10^-19) - (7.00151 x 10^-19)

E = <em>2.085 x 10^-20 J</em>

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