Wesley sailed his boat north for 18 miles then due east for another 18 miles approximately how far is Wesley from where he began

Mathematics

2 answers:

True [87]3 years ago

5 0

18 miles north
+18 miles east
=36 miles northeast

Dennis_Churaev [7]3 years ago

4 0

Answer:

Wesley is approximately 25.46 miles far from where he began

Step-by-step explanation:

Distance by which the boat is sailed in North = 18 miles

Distance by which the boat is sailed east = 18 miles.

So, The distance traveled by him is in the form of right angled and to find the distance between finial and initial position, we need to calculate the hypotenuse side.

⇒ Hypotenuse² = 18² + 18²

= 324 + 324 = 25.46 miles.

Hence, Wesley is approximately 25.46 miles far from where he began

You might be interested in

Is y = 7/8x proportional or non-proportional??

kati45 [8]

Answer:

It is proportional

Step-by-step explanation:

May have brainllest I only need 39 more to get to genius

5 0

2 years ago

Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$