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likoan [24]
3 years ago
13

What is the difference between visible light and x rays

Physics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer: X rays are high energy electromagnetic waves, but visible light is medium energy electromagnetic waves.

The visible spectrum is very narrow compared to the X-ray spectrum.

X rays can penetrate the human body but visible light is not capable of doing that. Hope this helped! :)

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The gravitational force between two objects will be greatest in which of the following situations?
Kobotan [32]

Answer:

Explanation:

Gravitational law states that, the force of attraction or repulsion between two masses is directly proportional to the product of the two masses and inversely proportional to the square of their distance apart.

So,

Let the masses be M1 and M2,

F ∝ M1 × M2

Let the distance apart be R

F ∝ 1 / R²

Combining the two equation

F ∝ M1•M2 / R²

G is the constant of proportional and it is called gravitational constant

F = G•M1•M2 / R²

So, to increase the gravitational force, the masses to the object must be increased and the distance apart must be reduced.

So, option c is correct

C. Both objects have large masses and are close together.

8 0
3 years ago
If the mass of a materials is 44grams and the volume of the material is 11cm^3 what would the density of the material be
jok3333 [9.3K]
Density =mass/volume
density= (0.044kg/(11 x10^-6)
4000kg/m^3
8 0
3 years ago
A charged particle is placed in an external magnetic field and it is moving in a circular path of radius 26m.The magnetic force
ElenaW [278]

Answer:

208 Joules

Explanation:

The radius of the circular path the charge moves, r = 26 m

The magnetic force acting on the charge particle, F = 16 N

Centripetal force, F_c = m·v²/r

Kinetic energy, K.E. = (1/2)·m·v²

Where;

m = The mass of the charged particle

v = The velocity of the charged particle

r = The radius of the path of the charged particle

Whereby the magnetic force acting on the charge particle = The centripetal force, we have;

F = F_c = m·v²/r = 16 N

(1/2) × r × F_c = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.

∴ (1/2) × r × F_c = (1/2) × 26 m × 16 N =  = (1/2)·m·v² = K.E.

∴ 208 Joules = K.E.

The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.

4 0
3 years ago
A portion of the mesosphere and thermosphere known for its ability to "bounce" radio signals is the _____________
Lerok [7]

It is B: ionosphere. This has the ability to bounce radio signals
8 0
3 years ago
What is the voltage in an electric current?
k0ka [10]
It is the energy of the electrons I believe
5 0
3 years ago
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