57.9 g of gold has a volume of 3 cm³ what is the density of gold in g/ centimeters cubed

Physics

2 answers:

Grace [21]3 years ago

7 0

D=m÷v

so density would be 57.9 ÷ 3 = 19.3 g/cm³

PolarNik [594]3 years ago

4 0

The answer is: " 20 g/cm³ " .
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Density = mass (g) per unit volume (cm³) ;

or: D = m / v ;

D = 57.9 g / 3 cm³ = (57.9 / 3) g / cm³ = 19.3 g / cm³ ;
→ round to "1 significant figure;
to get: 20 g / cm³
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Explanation:

Statement is incorrectly written. The correct form is: A $+10\,\mu C$ charge and a $-10\,\mu C$ at a distance of 0.3 meters.

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Where:

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$\kappa$ - Electrostatic constant, in newton-square meters per square coulomb.

$|q_{A}|,|q_{B}|$ - Magnitudes of electric charges, in coulombs.

$r$ - Distance between charges, in meters.

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