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lara31 [8.8K]
3 years ago
7

57.9 g of gold has a volume of 3 cm³ what is the density of gold in g/ centimeters cubed

Physics
2 answers:
Grace [21]3 years ago
7 0
D=m÷v

so density would be 57.9 ÷ 3 = 19.3 g/cm³
PolarNik [594]3 years ago
4 0
The answer is:  " 20 g/cm³ " .
________________________________________________
Density = mass (g) per unit volume (cm³) ; 

or:  D = m / v ; 

D  =  57.9 g / 3 cm³   =  (57.9 / 3)  g / cm³  = 19.3 g / cm³ ;
                                                      → round to "1 significant figure; 
                                                     to get:  20 g / cm³
_____________________________________________________
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An engineer can increase the magnitude of the magnification of a compound microscope by
jok3333 [9.3K]

Answer:

Option B

Explanation:

Magnification of Microscope is  

M = M_o \times M_e

Mo= Magnification of objective lens and

Me= magnification of the eyepiece.  

Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.  

Magnification,  

M\ \alpha\ \dfrac{1}{f}

when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.

Thus. Magnification will increase by decreasing the focal length.

The correct answer is Option B i.e. using shorter focal length

6 0
3 years ago
The magnitude of the momentum of an object is the product of its mass m and speed v. If m = 3 kg and v = 1.5 m/s, what is the ma
Oliga [24]

Answer:

Momentum, p = 5 kg-m/s

Explanation:

The magnitude of the momentum of an object is the product of its mass m and speed v i.e.

p = m v

Mass, m = 3 kg

Velocity, v = 1.5 m/s

So, momentum of this object is given by :

p=3\ kg\times 1.5\ m/s

p = 4.5 kg-m/s

or

p = 5 kg-m/s

So, the magnitude of momentum is 5 kg-m/s. Hence, this is the required solution.

5 0
3 years ago
answer this question: When you can not see what is taking place, but other senses indicate occurrences. This is called _________
Phoenix [80]
This is called an indirect observation.
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3 years ago
What is the momentum of an 18-kg object moving at 0.1 m/s ?
Anit [1.1K]

Answer:

1.8 m/s

Explanation:

here's the solution : -

momentum = mass × velocity

=》18 × 0.1

=》1.8 m/s

6 0
3 years ago
What is the magnitude of the electric force on an electron in a uniform electric field of strength 2050 n/c that points due east
erastova [34]
Given E=2050 N/C

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USING E = F/Q , electric field = force ÷ charge

2050 = F ÷ (1.6×10^-19)....

make F subject of formula and get the answer 
3 0
3 years ago
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