<span>A spatial pattern arranges main points according to physical direction or location.</span>
Answer:

Explanation:
According to given:
- molecular mass of glycerin,

- molecular mass of water,

- ∵Density of water is

- ∴mass of water in 316 mL,

- mass of glycerin,

- pressure of mixture,

- temperature of mixture,

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>
<u>moles of water in the given quantity:</u>



<u>moles of glycerin in the given quantity:</u>



<u>Now the mole fraction of water:</u>



<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>



Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).
I=1/(d*d)
Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.
L1/L2=(D2*D2)/(D1*D1)
L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 <span>candela</span>