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3 years ago

Numbers like 10 100 1000 and so on are called

Mathematics

2 answers:

Ad libitum [116K]3 years ago

6 0

Powers of ten, and they're easy to represent as exponents.<span />

valentina_108 [34]3 years ago

6 0

They are all called powers of 10

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2t+8=10 solve the equation

neonofarm [45]

Answer:

t = 1

Step-by-step explanation:

2t + 8 = 10

2t = 2 (-8 on both sides)

t = 1 (divide 2 on both sides)

7 0

3 years ago

Read 2 more answers

(-10) - |(-20) – (+30) |

myrzilka [38]

ANSWER: -60

EXPLANATION: To solve for (-10) - |(-20) – (+30) |, we need to do:

−10−| −20 − 30|, which equals −10−|−50|. Next, we do −10−50, which is -60.

−10−|−20−30|

= −10−|−50|

= −10−50

= −60

6 0

3 years ago

If f(2) = 13 and f '(x) ≥ 2 for 2 ≤ x ≤ 7, how small can f(7) possibly be?

timofeeve [1]

Answer:

Step-by-step explanation:

We are given that

f(2)=13

$f'(x)\geq 2$

$2\leq x\leq 7$

We have to find the possible small value of f(7).

We know that

$f'(x)=\frac{f(b)-f(a)}{b-a}$

Using the formula

$f'(x)=\frac{f(7)-f(2)}{7-2}$

$f'(x)=\frac{f(7)-13}{5}$

We have

$f'(x)\geq 2$

$\frac{f(7)-13}{5}\geq 2$

$f(7)-13\geq 2\times 5$

$f(7)-13\geq 10$

$f(7)\geq 10+13$

$f(7)\geq 23$

The small value of f(7) can be 23.

3 0

3 years ago

Ayden has exactly $1,725.50 to spend on a 7 - day vacation. If Ayden spends all of his money during the 7 - day span, what will

Fantom [35]

He would spend 246.5 each day because you would divide 1,725.50 by 7 and get 246.5

5 0

3 years ago

Read 2 more answers

A 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec. What is the rate that the tip of the pers

Dovator [93]

Answer:

9.56 ft/sec

Step-by-step explanation:

We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.

I've attached an image showing triangle that depicts this;

Thus; dx/dt = 3.4 ft/sec

From the attached image and using principle of similar triangles, we can say that;

9/y = 5.8/(y - x)

9(y - x) = 5.8y

9y - 9x = 5.8y

9y - 5.8y = 9x

3.2y = 9x

y = 9x/3.2

dy/dx = 9/3.2

Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;

dy/dt = dy/dx × dx/dt

dy/dt = (9/3.2) × 3.4

dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec

5 0

3 years ago