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weqwewe [10]
3 years ago
15

Why do you think the combined wave is more powerful than either the transverse or longitudinal wave with the same amplitude

Physics
1 answer:
liq [111]3 years ago
6 0

Answer:

Explanation:

The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,

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When a bond Norma between two or more elements, what part of the atom is forming the bond?
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The electrons are the only part of the atom that forms the bond
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A ball of mass 0.50 kg is fired with velocity 120 m/s into the barrel of a spring gun of mass 1.6 kg initially at rest on a fric
Gre4nikov [31]

Answer:

The fraction of the ball's kinetic energy stored in the spring is 3.6KJoules

Explanation:

Given

Mass of ball =0.5kg

Velocity of ball =120m/s

The kinetic energy stored by the ball is expressed as

K.E=1/2(m*v²)

Substituting our data into the expression we have

K. E=(0.5*120²)/2

K. E=7200/2

K.E=3,600 JOULE

K.E=3.6KiloJoules

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3 years ago
The grid in a triode is kept negatively charged to prevent...
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I think the correct answer is the third statement, electron from escaping from the tube containing the triode. The negative charge on the grid repels any electron in the tube. As a result,the flow of current is controlled. If the field is that strong, all current flow will stop resulting to maintaining the electron cloud in the tube. 
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3 years ago
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Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
6. DRAW 3 3/8° LINE<br> 7. DRAW A 5* LINE
Fiesta28 [93]

Answer:

Each part so obtained will represent the fraction 1/8 and the number line obtained will be of the form: To mark 3/8; move three parts on the right-side of zero. To mark 5/8; move five parts on the right-side of zero. To mark -1 3/8 i.e. -11/8; move eleven parts on the left-side of zero.

Explanation:

5 0
4 years ago
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