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weqwewe [10]
3 years ago
15

Why do you think the combined wave is more powerful than either the transverse or longitudinal wave with the same amplitude

Physics
1 answer:
liq [111]3 years ago
6 0

Answer:

Explanation:

The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,

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5/6 When switched on, the grinding machine accelerates from rest to its operating speed of 3450 rev/min in 6 seconds. When switc
ludmilkaskok [199]

Answer:

Δθ₁ =  172.5 rev

Δθ₁h =  43.1 rev

Δθ₂ =   920 rev

Δθ₂h = 690 rev

Explanation:

  • Assuming uniform angular acceleration, we can use the following kinematic equation in order to find the total angle rotated during the acceleration process, from rest to its operating speed:

       \Delta \theta = \frac{1}{2} *\alpha *(\Delta t)^{2}  (1)  

  • Now, we need first to find the value of  the angular acceleration, that we can get from the following expression:

       \omega_{f1}  = \omega_{o} + \alpha * \Delta t  (2)

  • Since the machine starts from rest, ω₀ = 0.
  • We know the value of ωf₁ (the operating speed) in rev/min.
  • Due to the time is expressed in seconds, it is suitable to convert rev/min to rev/sec, as follows:

       3450 \frac{rev}{min} * \frac{1 min}{60s} = 57.5 rev/sec (3)

  • Replacing by the givens in (2):

       57.5 rev/sec = 0 + \alpha * 6 s  (4)

  • Solving for α:

       \alpha = \frac{\omega_{f1}}{\Delta t} = \frac{57.5 rev/sec}{6 sec} = 9.6 rev/sec2 (5)

  • Replacing (5) and Δt in (1), we get:

       \Delta \theta_{1} = \frac{1}{2} *\alpha *(\Delta t)^{2} = \frac{1}{2} * 6.9 rev/sec2* 36 sec2 = 172.5 rev  (6)

  • in order to get the number of revolutions during the first half of this period, we need just to replace Δt in (6) by Δt/2, as follows:

       \Delta \theta_{1h} = \frac{1}{2} *\alpha *(\Delta t/2)^{2} = \frac{1}{2} * 6.9 rev/sec2* 9 sec2 = 43.2 rev  (7)

  • In order to get the number of revolutions rotated during the deceleration period, assuming constant deceleration, we can use the following kinematic equation:

       \Delta \theta = \omega_{o} * \Delta t + \frac{1}{2} *\alpha *(\Delta t)^{2}  (8)

  • First of all, we need to find the value of the angular acceleration during the second period.
  • We can use again (2) replacing by the givens:
  • ωf =0 (the machine finally comes to an stop)
  • ω₀ = ωf₁ = 57.5 rev/sec
  • Δt = 32 s

       0 = 57.5 rev/sec + \alpha * 32 s  (9)

  • Solving for α in (9), we get:

       \alpha_{2}  =- \frac{\omega_{f1}}{\Delta t} = \frac{-57.5 rev/sec}{32 sec} = -1.8 rev/sec2 (10)

  • Now, we can replace the values of ω₀, Δt and α₂ in (8), as follows:

        \Delta \theta_{2}  = (57.5 rev/sec*32) s -\frac{1}{2} * 1.8 rev/sec2\alpha *(32s)^{2} = 920 rev (11)

  • In order to get finally the number of revolutions rotated during the first half of the second period, we need just to replace 32 s by 16 s, as follows:
  • \Delta \theta_{2h}  = (57.5 rev/sec*16 s) -\frac{1}{2} * 1.8 rev/sec2\alpha *(16s)^{2} = 690 rev (12)
7 0
3 years ago
There is a reflection at the boundary between two materials if there is a change of __________ at the boundary.
melisa1 [442]
<span>The speed of the light in the materials. Hope this helps!!</span>
8 0
3 years ago
The model shows the star Wolf 359, the sun, and Star X. It takes 7.8 years for light produced on Wolf 359 to reach the sun.
saul85 [17]

Answer:

390 light-years

Explanation:

50 x 7.8 =390

4 0
3 years ago
What is the velocity of a worm moving 1 meter in 2 hours to the East?
malfutka [58]

Answer:

Velocity = 0.0001389 m/s

Explanation:

Given that the

Distance covered = 1 metre

Time taken = 2 hours

Convert the hour to second

1 hour = 60 × 60 = 3600

2 hours = 2 × 3600 = 7200

What is the velocity of a worm moving 1 meter in 2 hours to the East?

Velocity can be referred as speed.

Velocity = distance/ time

Velocity = 1/7200

Velocity = 0.0001389 m/s

3 0
4 years ago
A light bulb is rated at 25 w when operated at 110 v. how much charge enters (and leaves) the light bulb in 1.0 hour?
DedPeter [7]

According to the current, the charge is 818.18 coulombs.

We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as

I = Q / t

where I is current, Q is charge and t is time.

From the question above, we know that

P = 25 W

V = 110 V

h = 1 hour = 3600 second

Calculate the current

P = V . I

25 = 110 . I

I = 0.23 A

By substituting the given parameters, we can calculate the charge

I = Q / t

0.23 = Q / 3600

Q = 818.18 coulombs

Hence, the charge is 818.18 coulombs.

Find more on current at: brainly.com/question/24858512

#SPJ4

4 0
1 year ago
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