The answer should be c....
Answer:
c.) 36E
Explanation:
The magnitude of the electric field is given by the expression
(1)
where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.
In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

Now we want to determine the electric field at a distance of
away. Substituting into (1), we find
(2)
We also know that
(3)
So combining (2) with (3), we find a relationship between the original field and the new field:

Explanation:
s = ut + 1/2 a t^2
375 = 0 * 5 + 1/2 * a * (5)^2
375 = 1/2 * a * 25
a = 375*2/25
a = 15* 2
a = 30m/sec^2
v = u + at
v = 0 + 30 * 5
v = 150 m/sec
hope it helps you
an object is more dense if there is more weight in the same area, its because of the amount of particles and the weight of the particles. eg, 1cm cubed of gold would weigh alot more than 1cm cubed polystyrene, so gold is more dense