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Phantasy [73]
3 years ago
15

A runner starts from a rest and speeds up with a constant acceleration . if she has gone a distance of 30 m at the point when sh

e reaches a speed of 8 m/s what is her acceleration
Physics
2 answers:
garik1379 [7]3 years ago
6 0

Answer:

a = 1.07 m/s^2

Explanation:

As we know that the runner starts from rest position

So here we can say

v_i = 0

now the distance moved by the runner is given as

d = 30 m

also we know that final speed of the runner will be

v_f = 8 m/s

now we know that

v_f^2 - v_i^2 = 2 a d

8^2 - 0 = 2(a)(30)

a = \frac{64}{60}

a = 1.07 m/s^2

arsen [322]3 years ago
5 0

Answer:

1.1 m/s

Explanation:

Apex

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Answer:

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Explanation:

(a)

Potential Energy: This is the energy of a body, due to its position. The S.I unit of potential energy is Joules (J).

The formula of potential energy in a stretched spring is

Ep = 1/2ke² .......................... Equation 1

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(b)

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I.e,

Ep = 1/2mv² ............. Equation 2

Where m = mass of the arrow, v = velocity of the arrow.

make v the subject of the equation

v = √(2Ep/m)............. Equation 3

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